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6 I think
It depends on how many times you throw it! On a single throw, the answer is 0.5
There is a 50% chance.
On one dice there are 3 even numbers out of 6. Those being 2, 4, and 6 which would give you a 3:6 chance on one dice. If you took the next nice and attempted it again you would again have a 3:6 chance. 3:6 + 3:6 = 6:12 or 1:2 chance. So you have approximately a 50% chance of rolling an even number followed by an even number using two 6 sided dice.
zero as you only have 3 dice, with the number 6 on them only once on each dice. so if you are lucky you can only throw 6 3 times using 3 dice.
When you throw a dice there is always 6 chances of getting a number; therefore the numbers greater that 4 are: 5 and 6 (2 options) in total there will be 2/6 chances will simplifies to 1/3
It depends on how many times you throw it! On a single throw, the answer is 0.5
There is a 50% chance.
The chances of getting a number greater than 4 on a standard 6 face dice is a 2/6 chance which simplifies to a 1/3 chance. This is because their are only 2 numbers greater than 4.
On one dice there are 3 even numbers out of 6. Those being 2, 4, and 6 which would give you a 3:6 chance on one dice. If you took the next nice and attempted it again you would again have a 3:6 chance. 3:6 + 3:6 = 6:12 or 1:2 chance. So you have approximately a 50% chance of rolling an even number followed by an even number using two 6 sided dice.
Of the 36 possible outcomes of a throw of two dice, all but two result in a sum other than 3. So Prob(Not a three) = 100*34/36 = 94.44... %
zero as you only have 3 dice, with the number 6 on them only once on each dice. so if you are lucky you can only throw 6 3 times using 3 dice.
When you throw a dice there is always 6 chances of getting a number; therefore the numbers greater that 4 are: 5 and 6 (2 options) in total there will be 2/6 chances will simplifies to 1/3
1-(5/6 x 5/6 x5/6)
The factors of 20 on a die are: 1,2,4,5 Therefore it is a 4 out of 6 chance you will roll one of the factors. In simplest form, a 2 out of 3 chance or 66 2/3 chance.
If you only need to get six one time, the probability is 1/6 from the first throw plus 1/6 from the second throw so there is a 2/6 chance or 1/3. If you need to get six on both throws then there is a 1/6 chance on the first throw and a 1/6 chance on the second so 1/6 times 1/6 is 1/36. If you want the sum of the two throws to be six then there are 36 possible combinations (1 and 1, 1 and 2, etc.) and five of those add up to six (1 + 5, 2 + 4, 3 + 3, 4 + 2, and 5 + 1) so the probability would be 5/36.
The probability is very, very small, because there are no heads marked anywhere on the dice.
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