-3
The probability of rolling at least one 2 when rolling a die 12 times is about 0.8878. Simply raise the probability of not rolling a 2 (5 in 6, or about 0.8333) to the 12th power, getting about 0.1122, and subtract from 1.
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
The probability of rolling snake eyes on any one throw is 1 in 36. The probability of NOT rolling a snake eyes is 35 in 36. The only outcome here which we do not desire is that in which a non-snake eye roll occurs four times in a row, therefore, we take (35/36)^4 to find the probability of NEVER getting a snake eyes, and then subtract that answer from 1 to get the chances for any outcome WITH at least one pair of snake eyes. The chances are 10.66% of getting at least one snake eyes in four rolls.
The probability of rolling at least one 2 in fifty rolls of a standard die is 1 - (5/6) 50, or about 0.99989012. This calculation starts by looking at the probability of not rolling a 2, which is 5/6. To repeat that 50 times in a row, you simply raise that to the 50th power, getting 0.000109885. Then you subtract the result from 1 to get the probability of not succeeding in not rolling a 2 in fifty tries. Expressed in normal "odds" notation, this is about (100000 - 11) in 100000, or about 99989 in 100000.
The probability of rolling a specific number on a fair six-sided dice is 1/6, as there are 6 equally likely outcomes. When rolling the dice 300 times, the probability of rolling that specific number on each roll remains 1/6, assuming the dice is fair and each roll is independent. Therefore, the probability of rolling that specific number at least once in 300 rolls can be calculated using the complement rule, which is 1 minus the probability of not rolling the specific number in all 300 rolls.
00
The probability of rolling at least one 2 when rolling a die 12 times is about 0.8878. Simply raise the probability of not rolling a 2 (5 in 6, or about 0.8333) to the 12th power, getting about 0.1122, and subtract from 1.
The probability of getting a sum of 2 at least once is 0.8155
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
The probability of rolling a 4 in a die is 1 in 6, or about 0.1667. The probability, then, of rolling a 4 in at least one of two dice rolls is twice that, or 2 in 6, or 0.3333. The probability of rolling a sum of 4 in two dice is 3 in 36, or 1 in 18, or about 0.05556.
The probability of rolling a 3 on a six-sided die in a single roll is 1/6. When rolling the die three times, the probability of getting at least one 3 can be calculated using the complement: first, find the probability of not rolling a 3 in three rolls, which is (5/6)³. Subtract this value from 1 to find the probability of rolling at least one 3 in three attempts.
one fourth
There is a rolling duffel luggage that takes a lot to tip over.
When rolling two number cubes (standard six-sided dice), the probability of not rolling a six on a single die is 5/6. Therefore, the probability of not rolling a six on both dice is (5/6) × (5/6) = 25/36. To find the probability of rolling at least one six, we subtract this result from 1: 1 - 25/36 = 11/36. Thus, the probability of rolling at least one six when rolling two dice is 11/36.
The least error prone way of doing this is to draw a 6x6 square of all the possiblities when rolling a pair of dice, where one is red and one blue, and work out the proportion of the combinations that sum to 7.
The outcome is that in at least one of the 50 rolls the die comes to rest with the number one (or one spot) uppermost.
To calculate the probability of getting at least four heads when flipping a coin six times, we can use the binomial probability formula. The total number of outcomes for six flips is (2^6 = 64). The probabilities for getting exactly four, five, and six heads can be calculated using the binomial formula, and their sum gives the total probability of getting at least four heads. This results in a probability of approximately 0.65625, or 65.625%.