pi*27 feet
Circumference of the pool = 2*pi*72 = 452.369 feet to 3 dp
a 27 foot round by 52 inch deep pool holds 18,550 gallons of water
I am assuming this is a circular pool. The answer is Pi r^2 which comes to 572.5SF
A 27-foot wide by 52-inch-deep round pool holds a maximum of about 18,551.7 gallons of water.
If you are asking about a 27' circumference pool, then the answer is 27'
The circumference of a circle with a 27 foot diameter is about 84.82 feet. (C = d x Pi).
Not likely
pi*27 feet
The circumference of a circle is calculated using the formula C = πd, where C is the circumference, π is approximately 3.14, and d is the diameter. In this case, the diameter is 27 feet, so the calculation would be C = 3.14 x 27. Therefore, the circumference of a 27 foot diameter circle would be approximately 84.78 feet.
The answer depends on what the 27' refers to: the radius, diameter or circumference of the pool. A pool which is 27' across will cover 572.6 square feet.
Circumference of a circle = 2*pi*radius or pi*diameter
Circumfence 2 x 15 x pi = 94 feet 3 inches
Circumference = 18 feet.Depth = not known.
Circumference of the circular pool: 20*pi feet
There are 5280 feet in a mile. So for a 15ft pool (5280 divided by 15) you would have to walk around 352 times to equal one mile.
Circumference of the pool = 2*pi*72 = 452.369 feet to 3 dp