The circumference of a 27-foot diameter circle is about 84.82 feet. (diameter x Pi = circumference).
pi*27 feet
Circumference of the pool = 2*pi*72 = 452.369 feet to 3 dp
a 27 foot round by 52 inch deep pool holds 18,550 gallons of water
Oh, dude, you're hitting me with some math now? Alright, so if the pool is 12 feet wide and 24 feet long, you just add up all the sides to get the perimeter, which is like the circumference for a rectangle. So, it's 12 + 12 + 24 + 24, which equals 72 feet. There you go, the circumference of a 12 x 24 foot pool is 72 feet.
I am assuming this is a circular pool. The answer is Pi r^2 which comes to 572.5SF
If you are asking about a 27' circumference pool, then the answer is 27'
The circumference of a circle with a 27 foot diameter is about 84.82 feet. (C = d x Pi).
Not likely
pi*27 feet
The circumference of a circle is calculated using the formula C = πd, where C is the circumference, π is approximately 3.14, and d is the diameter. In this case, the diameter is 27 feet, so the calculation would be C = 3.14 x 27. Therefore, the circumference of a 27 foot diameter circle would be approximately 84.78 feet.
The answer depends on what the 27' refers to: the radius, diameter or circumference of the pool. A pool which is 27' across will cover 572.6 square feet.
Circumference of a circle = 2*pi*radius or pi*diameter
Circumfence 2 x 15 x pi = 94 feet 3 inches
Circumference = 18 feet.Depth = not known.
Circumference of the circular pool: 20*pi feet
There are 5280 feet in a mile. So for a 15ft pool (5280 divided by 15) you would have to walk around 352 times to equal one mile.
Circumference of the pool = 2*pi*72 = 452.369 feet to 3 dp