You forgot to copy the polynomial. However, the Fundamental Theorem of Algebra states that every polynomial has at least one root, if complex roots are allowed. If a polynomial has only real coefficients, and it it of odd degree, it will also have at least one real solution.
The polynomial (7x^2 - 3x + 4) is a quadratic polynomial because its highest degree term is (x^2), which indicates that it is a second-degree polynomial. Quadratic polynomials generally take the form (ax^2 + bx + c), where (a), (b), and (c) are constants, and in this case, (a = 7), (b = -3), and (c = 4).
821. The explantion is that they can be generated by the polynomial below: the only polynomial of degree 4. There are infinitely many other possibilities and given any "next number" it is possible to find a polynomial of degree 5 that will generate the 5 given numbers and the specified "next". Un = (53n4 - 486n3 + 1627n2 - 2250n + 1068)/12 for n = 1, 2, 3, ...
The correct set of coefficient for an equation depends with the equation in question. There are many types of equations.
To determine which binomial is a factor of a given polynomial, you can apply the Factor Theorem. According to this theorem, if you substitute a value ( c ) into the polynomial and it equals zero, then ( (x - c) ) is a factor. Alternatively, you can perform polynomial long division or synthetic division with the given binomials to see if any of them divides the polynomial without a remainder. If you provide the specific polynomial and the binomials you're considering, I can assist further.
There is no polynomial below.(Although I'll bet there was one wherever you copied the question from.)
10
You forgot to copy the polynomial. However, the Fundamental Theorem of Algebra states that every polynomial has at least one root, if complex roots are allowed. If a polynomial has only real coefficients, and it it of odd degree, it will also have at least one real solution.
The polynomial (7x^2 - 3x + 4) is a quadratic polynomial because its highest degree term is (x^2), which indicates that it is a second-degree polynomial. Quadratic polynomials generally take the form (ax^2 + bx + c), where (a), (b), and (c) are constants, and in this case, (a = 7), (b = -3), and (c = 4).
None does, since there is no polynomial below.
We can't answer that without knowing what the polynomial is.
According to the rational root theorem, which of the following are possible roots of the polynomial function below?F(x) = 8x3 - 3x2 + 5x+ 15
Answer this ques Which polynomial represents the sum below?(-x3 + 3x2 + 3) + (3x2 + x + 4)tion…
90
821. The explantion is that they can be generated by the polynomial below: the only polynomial of degree 4. There are infinitely many other possibilities and given any "next number" it is possible to find a polynomial of degree 5 that will generate the 5 given numbers and the specified "next". Un = (53n4 - 486n3 + 1627n2 - 2250n + 1068)/12 for n = 1, 2, 3, ...
What value, in place of the question mark, makes the polynomial below a perfect square trinomial?x2 + 12x+ ?
13x(x+3x)