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Step 1. Determine the total column height (in inches) as follows:

Total column height (in inches) = column height (in feet) x 12

13′ x 12″ = 156″Step 2. Enter the 24-inch cross-sectional dimension column in Table 1 at 13 feet. Step 3. · 3a. Determine the maximum (total) yoke spacing as follows:

Maximum (total) yoke spacing = sum of all but the last yoke spacing

found in the column

Yoke: 2d 3d 4th 5th 6th 7th 8th 9th

Yoke spacing:11″ + 12″ + 13″ + 14″ + 16″ + 22″ + 23″ + 23″ = 134″

Q: What is the column height in inches of the sixth yoke if a column is 10 feet high with a cross sectional dimension of 30 inches?

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height + width + depth = linear Previous answer: 45 linear inches

in simple math terms it is the length times height of a 2 dimension object the units are squared so if the length is five in and the height is 4 inches then the area would be 20 inches^2(squared)

To do this, you first need to convert the height into inches, so we're working with consistent units. 1 metre converts to 39.37 inches, so we can rewrite the question as what is the volume of a cylinder height 39.37 inches and radius 10 inches. First find the cross-sectional area: =pi(r2) =pi(100) =314.159 Then multiply this by the height 314.159 x 39.37 = 12,368 And so the volume is 12,400 inches3

8.125 inches

To start, we will find the cross sectional area of the pipes. Pipe with radius of 2 inches Cross sectional area = PI x radius2 = 12.56 inches2 Pipe with radius of 3 inches Cross sectional area = PI x radius2 = 28.26 inches2 Pipe with radius of 5 inches Cross sectional area = PI x radius2 = 78.5 inches2 As the cross sectional area of the pipe with a radius of 5 inches (78.5 inches2) is greater than the sum of the cross sectional areas of the pipes with radii of 2 inches and 3 inches (40.82 inches2), it can be concluded that the pipe with a radius of 5 inches will be able to carry the most water. (Assuming that all three pipes are the same length).

Related questions

height + width + depth = linear Previous answer: 45 linear inches

Because it is simply a linear measurement it has one dimension. Therefore it has no width or height.

A typical cereal box dimension is around 12 inches in height, 8 inches in width, and 3 inches in depth.

35 inches of water is equivalent to approximately 1.27 psi. This can be calculated by dividing the height of the water column (35 inches) by the conversion factor (27.71 inches of water column per psi).

To convert inches of water column to volume, you would need to know the area over which the water column is acting. Once you have the area, you can calculate the volume by multiplying the inches of water column by the area in square inches. The formula would be: Volume = Inches of water column * Area.

in simple math terms it is the length times height of a 2 dimension object the units are squared so if the length is five in and the height is 4 inches then the area would be 20 inches^2(squared)

4.5 inches

The linear dimension 62 inches is equal to the metric linear dimension 1.5748 meters

in simple math terms it is the length times height of a 2 dimension object the units are squared so if the length is five in and the height is 4 inches then the area would be 20 inches^2(squared)

To do this, you first need to convert the height into inches, so we're working with consistent units. 1 metre converts to 39.37 inches, so we can rewrite the question as what is the volume of a cylinder height 39.37 inches and radius 10 inches. First find the cross-sectional area: =pi(r2) =pi(100) =314.159 Then multiply this by the height 314.159 x 39.37 = 12,368 And so the volume is 12,400 inches3

The total sum of the length, height, and width of a single piece of luggage. For example. a cube 4 inches on a side with a volume of 64 cubic inches has a linear dimension of 12 inches.

The dimension is 1, of Length or [L].