16.387 cc is equal to one cubic inch of water or anything else.
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To convert inches of water column to volume, you would need to know the area over which the water column is acting. Once you have the area, you can calculate the volume by multiplying the inches of water column by the area in square inches. The formula would be: Volume = Inches of water column * Area.
One cubic inch is equal to 1 inch x 1 inch x 1 inch, which is 1 cubic inch.
To calculate the volume of water in the column, use the formula for the volume of a cylinder: pi * radius^2 * height. Convert the measurements: the radius is half of the diameter (6 inches), so 3 inches, convert height to feet (400 feet), and convert the result to gallons (1 cubic foot = 7.48 gallons).
The weight of a column of water can be calculated using the formula: weight = volume x density x gravity. For a 100-foot column of water that is 4 inches in diameter, the volume would be 2520 cubic inches. Assuming a density of water as 62.4 lbs/ft^3 and gravity as 9.81 m/s^2, the weight would be approximately 1085 pounds.
To calculate the volume of water needed to raise the level of the pool by 1 inch, you can use the formula: Volume = Length x Width x Height. Convert the dimensions to feet and calculate the volume accordingly. For a 16x32 pool and raising the level by 1 inch, you would need approximately 133.33 gallons of water.
The question as posed is unanswerable. In order to compute the weight of an inch of water, one would have to know the volume, or area the one inch covers. (ie., a square foot of water one inch deep would weigh=X)