y = mx + b, where m is the slope and b is the y-intercept.
Y=mc+b
A straight line in slope-intercept format has the equation: y = mx + b Where m is the slope, b the y-intercept. So, all you have to do is copy this equation, then replace "m" by the given slope, and "b" by the given y-intercept.
Slope = 0, intercept = 3
y = 0. You can get this from the slope-intercept equation of the line.
y = mx + b, where m is the slope and b is the y-intercept.
Y=mc+b
A straight line in slope-intercept format has the equation: y = mx + b Where m is the slope, b the y-intercept. So, all you have to do is copy this equation, then replace "m" by the given slope, and "b" by the given y-intercept.
y = {slope}x + {y intercept}
Slope = 0, intercept = 3
Normally yes, but if the slope passes through the origin (0, 0) then it will have no y intercept.
If you mean: y = -4x then the slope is -4 and there is no y intercept because the line cuts through the origin at (0, 0)
An equation in slope intercept form is given by y = mx + b, where m is the slope and b is the y-intercept.Examples:If the slope is 3 and the y- intercept is 4, the equation will be, y = 3x + 4If the slope is -1/5 and y-intercept is -2/3, the equation will be, y = -1/2)x - 2/3
There is no y intercept and the slope of the line is 12 from the origin
If you're given an existing point and the slope of the line, then yes - the y-intercept depends on the slope.
The slope is -5. The x- and y-intercepts are both zero. In other words, it passes through the origin.
The equation of a line in slope-intercept form is given by y = mx + b, where "m" represents the slope of the line and "b" represents the y-intercept.