2
A constant in an algebraic expression is a number that does not change. For example x + 2 The 2 is a constant (does not change) x is a variable (can take on any value)
Constant TermDefinition of Constant TermThe Constant Term in an expression or equation has a fixed value and does not contain variables.Examples of Constant TermThe constant term in the equation 6x2 - 3x + 5 is 5.Solved Example on Constant TermChoose the value of the constant term in the expression,- 12x2 + 5x +1.Choices:A. 5B. 1C. 0D. - 12Correct Answer: BSolution:Step 1: - 12x2 + 5x +1. [Original expression.]Step 2: The Constant Term in an algebraic expression or equation has a fixed value and does not contain variables.Step 3: Therefore, 1 is the constant term in the expression, - 12x2 + 5x +1.There You Go Baby ;]
Chord constant = ((A x B)/2)x1000 Radius = chord constant/versine So a 10m chord versine measured at 5m: ((5x5)/2)x1000 = CC 12.5x1000= 12500 CC/V = r 12500/30 = 416
21
what is the constant in algebraic experssion 7d+2
2
2
a, whatever the value is, would be the constant.
2 (or + 2)
A constant in an algebraic expression is a number that does not change. For example x + 2 The 2 is a constant (does not change) x is a variable (can take on any value)
Constant TermDefinition of Constant TermThe Constant Term in an expression or equation has a fixed value and does not contain variables.Examples of Constant TermThe constant term in the equation 6x2 - 3x + 5 is 5.Solved Example on Constant TermChoose the value of the constant term in the expression,- 12x2 + 5x +1.Choices:A. 5B. 1C. 0D. - 12Correct Answer: BSolution:Step 1: - 12x2 + 5x +1. [Original expression.]Step 2: The Constant Term in an algebraic expression or equation has a fixed value and does not contain variables.Step 3: Therefore, 1 is the constant term in the expression, - 12x2 + 5x +1.There You Go Baby ;]
The equilibrium constant expression for H2SO3 is K = [H+]^2[HSO3-]/[H2SO3].
The correct form for the equilibrium constant expression for this reaction is Kc = [HF]^2 / ([H2] * [F2]), where the square brackets denote molar concentrations of each species at equilibrium.
4
10 x .2 = 2.
100m^2-49n^2 (10m+7n)(10m-7n) the middle term cancels out.