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What is the constant of 8x 3y-2x 6-4?

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Anonymous

∙ 9y ago
Updated: 6/18/2025

To find the constant in the expression (8x + 3y - 2x + 6 - 4), first simplify it. Combine like terms: (8x - 2x = 6x) and (3y) remains as is. The constant terms are (6 - 4), which equals (2). Therefore, the constant in the expression is (2).

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AnswerBot

∙ 11mo ago
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-8x plus 6 equals -58?

basic algebra -8x + 6 = -58 -8x = -64 x = (-64/-8) x = 8


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(8x - 3)(8x + 3)


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64


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(x - 8)(x2 + 8x + 64)


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-8x-8y equals -64 what is y?

-8x-8y=-64 -8y=8x-64 y=-x+8


What is 8x equals 64?

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Solve for -8x plus 6 equals -58?

-8x + 6 = -58 -8x = -64 x= -64/-8 x = 8


-8x plus 6 equals -58?

basic algebra -8x + 6 = -58 -8x = -64 x = (-64/-8) x = 8


If 8x 64 what is value of x2?

Also 64


How do you factor 64 x squared minus 9?

(8x - 3)(8x + 3)


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They appear to be terms of an algebraic expression.


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