Q: What is the constant of 8x 3y-2x 6-4?

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-8x-8y=-64 -8y=8x-64 y=-x+8

72

-8x + 6 = -58 -8x = -64 x= -64/-8 x = 8

basic algebra -8x + 6 = -58 -8x = -64 x = (-64/-8) x = 8

Also 64

(8x - 3)(8x + 3)

64

64

-64

64

They appear to be terms of an algebraic expression.

4x+8x= 64