Q: What is the constant of variation for the quadratic variation 6y equals 4x2?

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If you can't factor it easily, use the quadratic formula.

By using the quadratic equation formula: (4x+1)(x-3) = 0

The domain is from negative infinity to positive infinity. The range is from positive 2 to positive infinity.

4x2 - 2x = 0

4x2 plus 3=11

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No. [ y = 4x2 ] is a quadratic equation.

Quadratic equation formula

If you can't factor it easily, use the quadratic formula.

By using the quadratic equation formula: (4x+1)(x-3) = 0

NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.

Using the quadratic equation formula:- x = -0.5447270865 or x = 2.294727086

The domain is from negative infinity to positive infinity. The range is from positive 2 to positive infinity.

The quadratic 4x2+24x+11 = (2x+1)(2x+11)

Interpreting this equation as y=4x3+4x2 This is not a quadratic equation. By definition, a quadratic equation is a polynomial equation of order two, meaning it is composed only of coefficients multiplied by x's raised to any exponential power of maximum 2. The most that any of the exponents in the equation can be is 2. Since this equation has a term of 4x3, it is not quadratic since this term has an exponent of 3. This means that the equation is of degree three. This equation is a cubic equation.

4x2 - 2x = 0

4x2 plus 3=11

4x2 - 4x + 1 = 0 => (2x - 1)(2x - 1) = 0 => (2x - 1)2 = 0 There is one solution: x = 1/2. It is a repeated root of the equation.