(2x + 3)(2x + 3)
4x2 - 13 x + 3 = 0 (4x - 1)(x - 3) = 0 x = 3, 1/4
4x2+49x+90 = (4x+9)(x+10) when factored
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
If you meant 2x+3=4x²x=(1±√(13))/4x1≈1.151387818866x2≈-0.651387818866
There are four solutions to 9x4 plus 27x3 - 4x2 - 12x equals 0. One of the solutions is x = -3.
(2x + 3)(2x + 3)
1/2 , 3/2
4x2 = -12x, divide both sides by 4x: x = -3
y=4x2+3x+8
4x2 - 12x + 9 = 5; whence, 2x - 3 = ±√5, and 2x = 3 ±√5. Therefore, x = ½ (3 ±√5).
4x2 - 13 x + 3 = 0 (4x - 1)(x - 3) = 0 x = 3, 1/4
4x2+49x+90 = (4x+9)(x+10) when factored
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
If you meant 2x+3=4x²x=(1±√(13))/4x1≈1.151387818866x2≈-0.651387818866
Solution: x = 1/4 and x = -3.
This is how I did it:8x3+4x2+6x+3[8x3+4x2]+[6x+3][(4x2)(2x+1)]+[(3)(2x+1)]....as you can see, this is in the general form of ab+cb, which factored is b(a+c), so:(2x+1)(4x2+3)