No.
y = 4 or y = any constant number.
33/4
y + 4 = 2x −1
(y-2) (x+4)
4
No.
y = 4 or y = any constant number.
33/4
(y^2 - 4) / (y + 2) = [(y -2)(y+2)]/(y+2) = y-2
y + 4 = 2x −1
(y-2) (x+4)
y^(3) - 2y^(2) + 4y Factor out 'y' Hence y(y^2 - 2y + 4) This will not factor any further.
y=-4x + 3 or generally y=mx + b so m, or gradient = -4
[ y = 2x plus or minus any number ] is parallel to it. [ y = -0.5x plus or minus any number ] is perpendicular to it.
-2
2