There are an infinite number of correct answers, because the square could be
located anywhere in the coordinate plane. Why, the thing could even be tilted;
its sides don't necessarily have to be parallel to the coordinate axes.
The simplest answer corresponds to a square in the First Quadrant with a corner
at the origin. Its vertices are located at:
(0, 0)
(0, 5)
(5, 5)
(5, 0)
The coordinates of a square can be defined by the positions of its four corners (vertices) in a Cartesian coordinate system. For example, if a square is centered at the origin with a side length of 2 units, its vertices could be at the coordinates (1, 1), (1, -1), (-1, -1), and (-1, 1). The specific coordinates will vary based on the square's size and position in the coordinate plane.
To find the area of a square, we need the length of one side. The given coordinates appear to be the x-coordinates of the vertices, but without the corresponding y-coordinates, we cannot determine the vertices' positions or calculate the side length. Assuming the vertices were intended to be (36, 31), (-21, 31), (-21, -26), and (36, -26), the side length would be the difference in the x-coordinates, which is 36 - (-21) = 57. Thus, the area would be (57^2 = 3249) square units.
A square has 5 vertices * * * * * A square has 4 vertices!
You can use the Pythagorean Theorem for this one. In other words, calculate square root of (difference-of-x-coordinates squared + difference-of-y-coordinates squared).
The answer depends on the shape of the quadrilateral and the form in which that information is given: for example, lengths of sides and angles, coordinates of vertices.
The coordinates of a square can be defined by the positions of its four corners (vertices) in a Cartesian coordinate system. For example, if a square is centered at the origin with a side length of 2 units, its vertices could be at the coordinates (1, 1), (1, -1), (-1, -1), and (-1, 1). The specific coordinates will vary based on the square's size and position in the coordinate plane.
To find the area of a square, we need the length of one side. The given coordinates appear to be the x-coordinates of the vertices, but without the corresponding y-coordinates, we cannot determine the vertices' positions or calculate the side length. Assuming the vertices were intended to be (36, 31), (-21, 31), (-21, -26), and (36, -26), the side length would be the difference in the x-coordinates, which is 36 - (-21) = 57. Thus, the area would be (57^2 = 3249) square units.
square root(x2-x1)squared+(y2-y1)squared
Assuming that these are coordinates of the vertices, the area is 6 square units.
A square has 5 vertices * * * * * A square has 4 vertices!
You can use the Pythagorean Theorem for this one. In other words, calculate square root of (difference-of-x-coordinates squared + difference-of-y-coordinates squared).
The answer depends on the shape of the quadrilateral and the form in which that information is given: for example, lengths of sides and angles, coordinates of vertices.
All rectangles are "squared" in that they have 4 corners (vertices) that are 90-degree angles. But a rectangle is only "a square" if all four sides are equal in length.
Clockwise from top right: (4,4); (4,-4); (-4,-4); (-4,4)
To get the coordinates of a square, you need to know the position of one vertex and the length of the sides. Assuming the square is aligned with the axes, if you have the coordinates of the bottom-left vertex (x, y) and the side length (s), the coordinates of the square's vertices would be (x, y), (x+s, y), (x, y+s), and (x+s, y+s). If the square is rotated or positioned differently, you may need additional information, such as the angle of rotation or the center point.
A square has 4 vertices
If the square has been plotted in a graph, you can go about finding the diagonal of it by measuring the midpoint. (1) Find the coordinates of the vertices of the square (2) Use the coordinates of two vertices that are across from each other. Plug them into the midpoint equation: (X1 + X2)/2 , (Y1 + Y2)/2, and use your answers as the coordinates of the midpoint (x,y) (3) Draw a straight line crossing through the midpoint from one opposite vertex to another. That is your diagonal.