Clockwise from top right: (4,4); (4,-4); (-4,-4); (-4,4)
Just find the midpoint of opposite corners Consider the rectangle with sides of length a and b. The length of a diagonal is then sqrt(a2+b2) The two diagonals cross at the midpoint or where the length of the line from one vertex to the center is one half of a diagonal or (0.5)[sqrt(a2+b2)]. 1- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and you have Point B(XB, YB) corresponding to the lower right coordinate of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated: XC = XA + (XB-XA)/2 YC = YA - (YA-XB)/2 2- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and the width (W) and height (H) of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated: XC = XA + (W)/2 YC = YA - (W)/2
The center of a coordinate plane is called the origin. The origin is the ordered pair (0,0).
Center
vertices
Spheres are the only shapes that have no vertices. A sphere is a three-dimensional shape that is perfectly round, with all points on its surface equidistant from its center. Unlike other three-dimensional shapes such as cubes or pyramids, spheres do not have any corners or vertices where edges meet.
The first step to finding a triangle's center of gravity is to calculate the average of the x-coordinates and y-coordinates of the triangle's vertices. This will give you the coordinates of the centroid, which is the point where the center of gravity lies.
To rotate a box around its center in MATLAB, you can use a rotation matrix. First, define the box's vertices in 3D space, then calculate the center by averaging the coordinates. Apply the rotation matrix, which is defined as ( R = \begin{bmatrix} \cos(\theta) & -\sin(\theta) \ \sin(\theta) & \cos(\theta) \end{bmatrix} ) for 2D or its 3D equivalent for 3D rotation, to the vertices after translating them to the origin (subtracting the center). Finally, translate the vertices back to their original position by adding the center coordinates.
'Centre of mass' is a place, i.e. a point, in space. It can be described by its coordinates . . . lengths (x, y, z) in Cartesian coordinates, or some combination of lengths and angles in other coordinate systems.
It helps to think as the sine and cosine as coordinates of a unit circle - a circle of radius 1, with center at the origin of the coordinates, i.e., point (0, 0). In this case, as you go around on the circle (starting at the right, coordinates (1, 0), and going counterclockwise), the cosine of the angle is simply the x-coordinate, and the sine of the angle is simply the y-coordinate. At 90°, the x-coordinate is 0, therefore the cosine is 0. Also, at 90° the y-coordinate is 1, therefore the sine is 1 (that's the maximum value it can have).
First I assume that you mean triangle and not traingle. The answer depends on the form in which you have information about the triangle.If the vertices of the triangle are known in terms of their coordinates: if the three vertices are (xa, ya), (xb, yb) and (xc, yc) then the CoG has the coordinates [(xa+xb+xc)/3, (ya+yb+yc)/3)].Otherwise, they CoG is the point where the medians of the triangle meet.
center center
The center of our galaxy is at a distance that is estimated to be between 25,000 and 28,000 light-years. As to the direction, it is in the constellation Sagittarius. If you want coordinates, the Wikipedia lists the following (article: galactic center): "In the Equatorial coordinate system they are: RA 17h45m40.04s, Dec -29° 00' 28.1" (J2000 epoch)."
In the system of Cartesian coordinates in geometry, the x-coordinate is the location in the horizontal direction (nominally left and right) while the y-coordinate is in the vertical direction (up and down). The line along which x values are measured is the x-axis. An x-coordinate to the left of center (zero) is negative, and to the right is positive. (In three dimensions, the x and y form a horizontal plane and the z coordinate is measured along the vertical axis.)
The centre of a coordinate plane is the point (0,0), also called the origin.
Cartesian coordinate system
If ... the square of (the x-coordinate of the point minus the x-coordinate of the center of the circle) added to the square of (the y-coordinate of the point minus the y-coordinate of the center of the circle) is equal to the square of the circle's radius, then the point is on the circle.
Just find the midpoint of opposite corners Consider the rectangle with sides of length a and b. The length of a diagonal is then sqrt(a2+b2) The two diagonals cross at the midpoint or where the length of the line from one vertex to the center is one half of a diagonal or (0.5)[sqrt(a2+b2)]. 1- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and you have Point B(XB, YB) corresponding to the lower right coordinate of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated: XC = XA + (XB-XA)/2 YC = YA - (YA-XB)/2 2- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and the width (W) and height (H) of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated: XC = XA + (W)/2 YC = YA - (W)/2