Clockwise from top right: (4,4); (4,-4); (-4,-4); (-4,4)
Just find the midpoint of opposite corners Consider the rectangle with sides of length a and b. The length of a diagonal is then sqrt(a2+b2) The two diagonals cross at the midpoint or where the length of the line from one vertex to the center is one half of a diagonal or (0.5)[sqrt(a2+b2)]. 1- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and you have Point B(XB, YB) corresponding to the lower right coordinate of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated: XC = XA + (XB-XA)/2 YC = YA - (YA-XB)/2 2- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and the width (W) and height (H) of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated: XC = XA + (W)/2 YC = YA - (W)/2
The center of a coordinate plane is called the origin. The origin is the ordered pair (0,0).
Center
vertices
The circumcenter of a triangle is the center of the circle drawn outside the triangle with all three vertices touching its circumference.
The middle point of a plane is often referred to as the "centroid" or "center." In a geometric context, the centroid is the average position of all points in a shape, while in a Cartesian coordinate system, the center can be defined as the point with coordinates that are the averages of the x and y coordinates of the vertices. In more general terms, it can also be called the "origin" if considering a coordinate plane where the origin is the point (0, 0).
The first step to finding a triangle's center of gravity is to calculate the average of the x-coordinates and y-coordinates of the triangle's vertices. This will give you the coordinates of the centroid, which is the point where the center of gravity lies.
To find the coordinates of a point after dilation, you multiply the original coordinates by the scale factor. If the point is represented as ( (x, y) ) and the scale factor is ( k ), the new coordinates become ( (kx, ky) ). If the dilation is from a center point other than the origin, you would first subtract the center coordinates from the point, apply the scale factor, and then add the center coordinates back to the result.
To rotate a box around its center in MATLAB, you can use a rotation matrix. First, define the box's vertices in 3D space, then calculate the center by averaging the coordinates. Apply the rotation matrix, which is defined as ( R = \begin{bmatrix} \cos(\theta) & -\sin(\theta) \ \sin(\theta) & \cos(\theta) \end{bmatrix} ) for 2D or its 3D equivalent for 3D rotation, to the vertices after translating them to the origin (subtracting the center). Finally, translate the vertices back to their original position by adding the center coordinates.
'Centre of mass' is a place, i.e. a point, in space. It can be described by its coordinates . . . lengths (x, y, z) in Cartesian coordinates, or some combination of lengths and angles in other coordinate systems.
The vertices of a pentagon are the five points where its sides meet. In a regular pentagon, these vertices are equidistant from the center and are evenly spaced around a circle. In general, the coordinates of the vertices can vary depending on the specific shape and size of the pentagon. For example, a regular pentagon inscribed in a unit circle has vertices at angles of (72^\circ) increments from a starting point.
It helps to think as the sine and cosine as coordinates of a unit circle - a circle of radius 1, with center at the origin of the coordinates, i.e., point (0, 0). In this case, as you go around on the circle (starting at the right, coordinates (1, 0), and going counterclockwise), the cosine of the angle is simply the x-coordinate, and the sine of the angle is simply the y-coordinate. At 90°, the x-coordinate is 0, therefore the cosine is 0. Also, at 90° the y-coordinate is 1, therefore the sine is 1 (that's the maximum value it can have).
First I assume that you mean triangle and not traingle. The answer depends on the form in which you have information about the triangle.If the vertices of the triangle are known in terms of their coordinates: if the three vertices are (xa, ya), (xb, yb) and (xc, yc) then the CoG has the coordinates [(xa+xb+xc)/3, (ya+yb+yc)/3)].Otherwise, they CoG is the point where the medians of the triangle meet.
center center
Yes, the origin is typically considered the center of a coordinate grid. In a two-dimensional Cartesian coordinate system, the origin is the point where the x-axis and y-axis intersect, represented by the coordinates (0, 0). In a three-dimensional grid, the origin is the point where the x, y, and z axes intersect, represented as (0, 0, 0). It serves as the reference point for defining the positions of other points in the grid.
To enlarge a figure on a coordinate graph, you can apply a dilation transformation using a scale factor. Choose a center point for the dilation, often the origin or the center of the figure, and multiply the coordinates of each vertex by the scale factor. For example, if you use a scale factor of 2, each coordinate (x, y) becomes (2x, 2y), effectively doubling the size of the figure while maintaining its shape and proportions.
The center of our galaxy is at a distance that is estimated to be between 25,000 and 28,000 light-years. As to the direction, it is in the constellation Sagittarius. If you want coordinates, the Wikipedia lists the following (article: galactic center): "In the Equatorial coordinate system they are: RA 17h45m40.04s, Dec -29° 00' 28.1" (J2000 epoch)."