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To find the corner-to-corner measurement (diagonal) of a 20' x 40' rectangle, you can use the Pythagorean theorem. The diagonal ( d ) is calculated as ( d = \sqrt{(20^2 + 40^2)} ). This results in ( d = \sqrt{(400 + 1600)} = \sqrt{2000} ), which simplifies to approximately 44.72 feet.
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What is the diagonal measurement of 40 and 30?
Assuming that the 40 and 30 refer to sides of a rectangle and not to any of the infinite number of other possible shapes, the answer is 50.
What is the perimeter of a rectangle 20 centimeters by 45 centimeters?
The perimeter of a rectangle measuring 20x45 centimeters is (2*20) + (2*45) = 40 + 90 = 130 cm
The perimeter of a rectangle is 50 centimeters The length of the rectangle is 20 centimeters What is the width of the rectangle?
Let the width be x: 2(length+width) = perimeter 2(20+x) = 50 40+2x = 50 2x = 50 -40 2x = 10 x = 5 centimeters Check: 5+5+20+20 = 50 centimeters
What is the perimeter of a rectangle with a length of 40 feet a width of 5.5 feet and a height of 20 feet?
You are describing a cuboid, not a rectangle. A rectangle has only two diminutions, length and width.
What is the area of a rectangle with a width of 20 feet and a length of 40 feet?
800 sq ft
What is the area of the rectangle in square inches 20 inches by 40 inches?
Area rectangle: 20 times 40 = 800 square inches
What is the diagonal measurement of a rectangle measuring 20 feet by 40 feet?
Using Pythagoras' theorem it works out as 20 times the square root of 5 which is about 44.721 feet to three decimal places.
What is the diagonal measurement of a rectangle measuring 24 feet by 40 feet?
46.648 ft
What is the diagonal measurement of 40' X 50'?
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 50' rectangle can be calculated as follows: diagonal = √(40^2 + 50^2) = √(1600 + 2500) = √4100 ≈ 64.03 feet.
What is the diagonal measurement of 40 and 30?
Assuming that the 40 and 30 refer to sides of a rectangle and not to any of the infinite number of other possible shapes, the answer is 50.
What is the perimeter of a rectangle 20 centimeters by 45 centimeters?
The perimeter of a rectangle measuring 20x45 centimeters is (2*20) + (2*45) = 40 + 90 = 130 cm
The perimeter of a rectangle is 50 centimeters The length of the rectangle is 20 centimeters What is the width of the rectangle?
Let the width be x: 2(length+width) = perimeter 2(20+x) = 50 40+2x = 50 2x = 50 -40 2x = 10 x = 5 centimeters Check: 5+5+20+20 = 50 centimeters
If a rectangle is 10 kilometers long and another side is 20 kilometers long what is the perimeter of the rectangle?
2 x 10 = 20 2 x 20 = 40 add them up 60km
What is the sum of the length of the diagonals of a 12 by 16 rectangle?
If the length of a rectangle is 12 and the width of the rectangle is 16, by the Pythagorean theorem we know that one diagonal is 20 units long. You can draw two diagonals within a rectangle, so the length of both diagonals together is 20+20 = 40 units.
What is the perimeter of a rectangle with a length of 40 feet a width of 5.5 feet and a height of 20 feet?
You are describing a cuboid, not a rectangle. A rectangle has only two diminutions, length and width.
What is the area of a rectangle with a width of 20 feet and a length of 40 feet?
800 sq ft
What is the length of the rectangle is 20 more than its width if the perimeter is 160 cm what are the dimension of the rectangle?
Let x be the unknown dimension x+x+x+20+x+20 = perimeter of the rectangle 4x+40 = 160 4x = 160-40 4x = 120 x = 30 Therefore the width is 30 cm and the length is 50 cm
