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To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 50' rectangle can be calculated as follows: diagonal = √(40^2 + 50^2) = √(1600 + 2500) = √4100 ≈ 64.03 feet.

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Q: What is the diagonal measurement of 40' X 50'?
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What is the diagonal measurement of 40' x 60'?

To find the diagonal measurement of a rectangle, we can use the Pythagorean theorem, which states that the square of the hypotenuse (diagonal) of a right triangle is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 60' rectangle can be calculated as follows: Diagonal = √(40^2 + 60^2) = √(1600 + 3600) = √5200 ≈ 72.11 feet. Therefore, the diagonal measurement of a 40' x 60' rectangle is approximately 72.11 feet.


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Oh, dude, you're asking me to bust out some high school math here. So, like, to find the diagonal of a rectangle, you use the Pythagorean theorem. It's like a^2 + b^2 = c^2, where a and b are the sides of the rectangle. In this case, it's 12^2 + 16^2 = c^2. So, the diagonal would be the square root of 400, which is 20.


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