To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 50' rectangle can be calculated as follows: diagonal = √(40^2 + 50^2) = √(1600 + 2500) = √4100 ≈ 64.03 feet.
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
Diagonal = 36.9 feet
17.8885'
The diagonal of the paver is about 848.53mm
About 8.5 feet.
To find the diagonal measurement of a rectangle, we can use the Pythagorean theorem, which states that the square of the hypotenuse (diagonal) of a right triangle is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 60' rectangle can be calculated as follows: Diagonal = √(40^2 + 60^2) = √(1600 + 3600) = √5200 ≈ 72.11 feet. Therefore, the diagonal measurement of a 40' x 60' rectangle is approximately 72.11 feet.
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
50 x 40 x 20 is not a linear measurement and so cannot be expressed in inches.
Diagonal = 36.9 feet
The diagonal of a 12' x 24' rectangle is approx 26.8'.
17.8885'
32.311
The diagonal of the paver is about 848.53mm
14.42 feet.
Oh, dude, you're asking me to bust out some high school math here. So, like, to find the diagonal of a rectangle, you use the Pythagorean theorem. It's like a^2 + b^2 = c^2, where a and b are the sides of the rectangle. In this case, it's 12^2 + 16^2 = c^2. So, the diagonal would be the square root of 400, which is 20.
116
That would be 34 feet.