How could it be? Where is the oxygen count? C7H16 + 11O2 -> 7CO2 + 8H2O
The reactants are the substances that react together; the reactants are on the left side of the equation. The product (or products) are what is produced from the reaction, which is on the right side of the equation. For example: 2H2 + O2 --> 2(H2O) The reactants are H2 & O2 and the product is H2O
2NH4NO3->2N2+O2+4H2O
2NaH2 + O2 yields 2Na + 2H2O
Simple application of Pythagoras Congruent side becomes the hypotenuse of a right-angled triangle with a known side of 5 (half the base). Doing the math we get the following: H2 = O2 + A2 92 = O2 + 52 rearranging we get O2 = 92 - 52 O2 = 81 - 25 O2 = 56 therefore O = √56 which is approximately 7.48 to decimal places
The balanced equation for the reaction between liquid heptane (C7H16) and oxygen (O2) is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O
The balanced equation for the combustion of heptane (C7H16) with oxygen (O2) is: C7H16 + 11O2 → 7CO2 + 8H2O
The balanced equation for the combustion of heptane is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O. Therefore, the coefficient for oxygen is 11.
Complete combustion of heptane, which has the chemical formula C7H16, produces carbon dioxide (CO2) and water (H2O) as the main products. The balanced chemical equation for the combustion of heptane is: C7H16 + 11 O2 → 7 CO2 + 8 H2O
How could it be? Where is the oxygen count? C7H16 + 11O2 -> 7CO2 + 8H2O
The formula for glucose is C6H12O6 not C6H12O8 which I believe is what you were trying to make in a chemical equation which would look like 6H2O+6CO2 ------->C6H12O6 The rest of the atoms are converted back into H2O and any excess oxygen is given off by the plants. That is the reason that we need plants to balance the carbon dioxide and oxygen levels in the atmosphere.
C7H16+11O2 = 7CO2+8H2O is the balanced equation for the complete combustion of heptane.
In the combustion of C7H16, 7 moles of O2 are required to form 8 moles of CO2. From the given 19.4g of CO2, 1 mole of CO2 is equivalent to 44g. Using stoichiometry, we can calculate that 25.23g of O2 are consumed during the combustion.
The balanced equation for complete combustion of heptane is C7H16 + 11O2 ---(ignition)---> 7CO2 + 8H2O. For each moelcule of heptane, you would need 11 molecules of oxygen gas.
The product for the reaction between PbO2 and O2 is PbO2.
2Cu + O2 ==> 2CuO product is copper(II) oxide4Cu + O2 ==> 2Cu2O product is copper(I) oxide
Photosynthesis is H2O + CO2 + sunlight becomes C6H12O6 (glucose) and O2, O2 or oxygen being the unneeded product.