-8x3 = -24 which has no square root in Real numbers. The square root of -24 is ±4.898979*i where i is the imaginary square root of -1.
-1X-1X-1=-1 therefore cube root of -1 = -1
The real cube root of 1 is 1, since 13 = 1. There also a pair of complex cube roots.
The cube root of 1 will also be 1. You can check with the complementary operation: 1*1*1=1 (true).
The cube root of -1 ("minus 1" or "negative 1") is -1. In fact all odd-numbered roots (i.e., the fifth root, the seventh root, the ninth root, etc.) of -1 are -1.
-8x3 = -24 which has no square root in Real numbers. The square root of -24 is ±4.898979*i where i is the imaginary square root of -1.
The number 27 has a cube root of 3, which is 2 (the smallest prime) plus 1.
-1X-1X-1=-1 therefore cube root of -1 = -1
the cube root of 125 is 5, the cube root of 64 is 4, the cube root of 27 is 3, the cube root of 8 is 2, and the cube root of 1 is 1.
The real cube root of 1 is 1, since 13 = 1. There also a pair of complex cube roots.
To find the cube root of a number, enter the number followed by ^(1/3).To find the cube root of a number, enter the number followed by ^(1/3).To find the cube root of a number, enter the number followed by ^(1/3).To find the cube root of a number, enter the number followed by ^(1/3).
The cube root of 1 will also be 1. You can check with the complementary operation: 1*1*1=1 (true).
The cube root of -1 ("minus 1" or "negative 1") is -1. In fact all odd-numbered roots (i.e., the fifth root, the seventh root, the ninth root, etc.) of -1 are -1.
1
Any root of 1 is equal to 1, because you can multiply 1 by itself any number of times, and the answer is still 1. Therefore, the cube root of 1 is 1.
This is how I did it:8x3+4x2+6x+3[8x3+4x2]+[6x+3][(4x2)(2x+1)]+[(3)(2x+1)]....as you can see, this is in the general form of ab+cb, which factored is b(a+c), so:(2x+1)(4x2+3)
1 and -1