11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
(01110111)2 = hexadecimal byte 77 = (119)10
The value of the 5 as a fraction is 1/2 or as a decimal is 0.5
The Hundreds place for the 2 before the decimal but the hundredths place for the 2 behind the decimal
The most significant byte (MSB) of a positive binary number is the decimal value of the left-most bit.For example, the binary number 10111001011 is 11 bits, meaning it's 11 digits long. Thus, the decimal value of the left-most bit, the MSB, is 1 X 210 = 1024. The reason why it's not 1 X 211 is that the decimal value of the right-most bit is represented by raising 2 to the 0th power, not the first power. In this case, the right-most bit has a decimal value of 1 X 20 = 1.
bool F1(int byte,int pos) { return(byte & 1<<pos) } //pos -> position in the field // say byte is b1011 and pos is 2 then it will return value 0
0.00195 KB equals 2 bytes
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
(01110111)2 = hexadecimal byte 77 = (119)10
There are two nibbles in a byte.
In a byte MSB is the bit that represents value 2^7, LSB is the bit that represents value 2^0.
The equivalent decimal for 2.70 is 2.70 itself. In decimal form, the number remains the same as the given value. This is because the number 2.70 is already in decimal form, representing 2 whole units and 70 hundredths.
The value of the 5 as a fraction is 1/2 or as a decimal is 0.5
It is the amount obtained when you divide the decimal number by 2.
0.5 is the only decimal that will qualify as a decimal value for 1/2
The Hundreds place for the 2 before the decimal but the hundredths place for the 2 behind the decimal
11b which is 1*2 + 1*1 = 3 would be for two bits. But a byte is 8 bits, so 2 bytes is 16 bits. The largest binary number is [2^16 - 1], which is 65535 (base ten)