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11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
(01110111)2 = hexadecimal byte 77 = (119)10
The value of the 5 as a fraction is 1/2 or as a decimal is 0.5
The Hundreds place for the 2 before the decimal but the hundredths place for the 2 behind the decimal
The most significant byte (MSB) of a positive binary number is the decimal value of the left-most bit.For example, the binary number 10111001011 is 11 bits, meaning it's 11 digits long. Thus, the decimal value of the left-most bit, the MSB, is 1 X 210 = 1024. The reason why it's not 1 X 211 is that the decimal value of the right-most bit is represented by raising 2 to the 0th power, not the first power. In this case, the right-most bit has a decimal value of 1 X 20 = 1.