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If you have a rectangular gold brick that is 2 cm by 3 cm by 4 cm and has a mass of 48 g what is the density?
Well, honey, density is mass divided by volume, so in this case, the volume of your gold brick is 2 cm x 3 cm x 4 cm, which equals 24 cm³. So, density = 48 g / 24 cm³, which gives you a density of 2 g/cm³. Voilà!
What is the density of a block of lead that had dimensions of 4.50 cm 5.20 cm 6.00 cm?
To find the density of the block of lead, first calculate its volume using the formula ( \text{Volume} = \text{length} \times \text{width} \times \text{height} ). For the given dimensions, the volume is ( 4.50 , \text{cm} \times 5.20 , \text{cm} \times 6.00 , \text{cm} = 140.4 , \text{cm}^3 ). The density of lead is approximately ( 11.34 , \text{g/cm}^3 ), so the mass of the block can be found by multiplying the volume by the density, resulting in a mass of about ( 1583.9 , \text{g} ). Thus, the density remains ( 11.34 , \text{g/cm}^3 ).
A piece of wood that measures 3.0 cm by 6.0 cm by 4.0 cm has a masd of 80.0 grams What is the density of the wood Would thr piece of wood float in water no?
To find the density of the wood, we first calculate its volume using the formula for the volume of a rectangular prism: ( V = length \times width \times height = 3.0 , \text{cm} \times 6.0 , \text{cm} \times 4.0 , \text{cm} = 72.0 , \text{cm}^3 ). Then, we calculate the density using the formula ( \text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{80.0 , \text{g}}{72.0 , \text{cm}^3} \approx 1.11 , \text{g/cm}^3 ). Since the density of water is 1.0 g/cm³, the wood, having a density greater than that, would not float in water.
What would the density be for 1000g lump of clay with a volume of 500cm3?
To calculate the density of the clay, use the formula: density = mass/volume. Given that the mass is 1000 grams and the volume is 500 cm³, the density would be 1000g / 500cm³ = 2 g/cm³. Therefore, the density of the clay is 2 g/cm³.
What is the density of a cube if each side is 2 cm and the mass is 16 grams?
Oh, dude, you're hitting me with some math here! So, the density of the cube is the mass divided by the volume. Since the cube has equal sides, the volume is just side cubed, which is 2 cm x 2 cm x 2 cm. That gives you a volume of 8 cubic cm. Divide the mass (16 grams) by the volume (8 cubic cm), and you get a density of 2 grams per cubic cm. Like, easy peasy, right?
Find the mass of a piece of ice that is in the shape of a rectangula prism that is 2 cm by 4 cm by 6 cm having a density of 0.92 g cm3?
44.16g density times volume
What is the density of an object that is 10 cm by 2 cm and has a mass 400g?
the density of an object that is 10 cm by 2 cm and has a mass 400g will be 10000 Kg m-3. This can be calculated by the formula, density = mass/volume
If you have a rectangular gold brick that is 2 cm by 3 cm by 4 cm and has a mass of 48 g what is the density?
Well, honey, density is mass divided by volume, so in this case, the volume of your gold brick is 2 cm x 3 cm x 4 cm, which equals 24 cm³. So, density = 48 g / 24 cm³, which gives you a density of 2 g/cm³. Voilà!
What is the density of a cubical block of side 2 cm with a mass 6.4 g?
Density is the mass divided by the volume. The mass is given as 6.4 grm so we have to calculate the volume. A cube of 2 cm per side has a volume of 2 x 2 x 2 equals 8 cm3. Thus the density of the substance is 6.4 divided by 8 equals 0.8 grm per cm3 (in c.g.s units) or 800 Kg per m3 (in SI units) This is less dense than water.
What is the density length10 cm width 5 cm height 2 cm mass 300 g?
The density of the object is 6 g/cm³. Density = mass/volume, mass is 300 g, volume is length x width x height = 10 cm x 5 cm x 2 cm = 100 cm³. Density = 300 g / 100 cm³ = 3 g/cm³.
What is the density of a piece of metal that has a mass of 6.29 times 10 to the power of 5 grams and is 96.4 cm times 49.1 cm times 81.7cm?
The density of this hypothetical metal will be 155,8 g/cm3.
What is the density of a block of lead that had dimensions of 4.50 cm 5.20 cm 6.00 cm?
To find the density of the block of lead, first calculate its volume using the formula ( \text{Volume} = \text{length} \times \text{width} \times \text{height} ). For the given dimensions, the volume is ( 4.50 , \text{cm} \times 5.20 , \text{cm} \times 6.00 , \text{cm} = 140.4 , \text{cm}^3 ). The density of lead is approximately ( 11.34 , \text{g/cm}^3 ), so the mass of the block can be found by multiplying the volume by the density, resulting in a mass of about ( 1583.9 , \text{g} ). Thus, the density remains ( 11.34 , \text{g/cm}^3 ).
A cube has a side 5.0 cm long It has a mass of 250 grams The density of the cube you?
The volume of the cube is (5.0 cm)^3 = 125 cm^3. To find the density, divide the mass by the volume: density = mass / volume = 250 g / 125 cm^3 = 2 g/cm^3. The density of the cube is 2 g/cm^3.
Which will float on a fluid that has a density of 2 grams cm and Acirc and sup3?
Any object which, if submerged, would displace 2 times its own volume. The density of the object could be well above 2 gms/cm^3. If that were not the case, then ships made of metal would never float in water. which has a much lower density.
A rectangular solid is 3 cm long 2 cm wide and 1 cm high it has a mass of 12 g what is its density?
The density of a material is defined as its mass per unit volume, density = m/v (mass/volume) One unit for this is grams/cm3. The weight is 12 g, and the volume is: v = 3 cm x 2 cm x 1 cm = 6 cm3 plugging in: density = m/v = 12 g/6cm3 = 2 g/cm3
A piece of wood that measures 3.0 cm by 6.0 cm by 4.0 cm has a masd of 80.0 grams What is the density of the wood Would thr piece of wood float in water no?
To find the density of the wood, we first calculate its volume using the formula for the volume of a rectangular prism: ( V = length \times width \times height = 3.0 , \text{cm} \times 6.0 , \text{cm} \times 4.0 , \text{cm} = 72.0 , \text{cm}^3 ). Then, we calculate the density using the formula ( \text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{80.0 , \text{g}}{72.0 , \text{cm}^3} \approx 1.11 , \text{g/cm}^3 ). Since the density of water is 1.0 g/cm³, the wood, having a density greater than that, would not float in water.
What would the density be for 1000g lump of clay with a volume of 500cm3?
To calculate the density of the clay, use the formula: density = mass/volume. Given that the mass is 1000 grams and the volume is 500 cm³, the density would be 1000g / 500cm³ = 2 g/cm³. Therefore, the density of the clay is 2 g/cm³.
