Well, honey, density is mass divided by volume, so in this case, the volume of your gold brick is 2 cm x 3 cm x 4 cm, which equals 24 cm³. So, density = 48 g / 24 cm³, which gives you a density of 2 g/cm³. Voilà!
What is the density of a rectangular object with the height of 5 cm the length of 10 cm, the width of 2 cm and the mass of 50 g
Oh, dude, you're hitting me with some math here! So, the density of the cube is the mass divided by the volume. Since the cube has equal sides, the volume is just side cubed, which is 2 cm x 2 cm x 2 cm. That gives you a volume of 8 cubic cm. Divide the mass (16 grams) by the volume (8 cubic cm), and you get a density of 2 grams per cubic cm. Like, easy peasy, right?
12, cause 2 times 3 =6 times 2=12 cm
So the answer is 2.447357008 x10 -03 g/cm cubed. Explanation: a) 5.54 cm times 10.6 cm times 199 cm = 11686.076 (volume= length times width times height) b) density = mass/volume so 28.6 divided by 11686.076 = 2.447357008 x10 -03
44.16g density times volume
the density of an object that is 10 cm by 2 cm and has a mass 400g will be 10000 Kg m-3. This can be calculated by the formula, density = mass/volume
Well, honey, density is mass divided by volume, so in this case, the volume of your gold brick is 2 cm x 3 cm x 4 cm, which equals 24 cm³. So, density = 48 g / 24 cm³, which gives you a density of 2 g/cm³. Voilà!
The volume of the cubical block is calculated as (2 \text{ cm} \times 2 \text{ cm} \times 2 \text{ cm} = 8 \text{ cm}^3). Density is calculated as mass divided by volume, so the density of the cubical block is (6.4 \text{ g} / 8 \text{ cm}^3 = 0.8 \text{ g/cm}^3).
The density of this hypothetical metal will be 155,8 g/cm3.
The density of the object is 6 g/cm³. Density = mass/volume, mass is 300 g, volume is length x width x height = 10 cm x 5 cm x 2 cm = 100 cm³. Density = 300 g / 100 cm³ = 3 g/cm³.
Any object which, if submerged, would displace 2 times its own volume. The density of the object could be well above 2 gms/cm^3. If that were not the case, then ships made of metal would never float in water. which has a much lower density.
The volume of the cube is (5.0 cm)^3 = 125 cm^3. To find the density, divide the mass by the volume: density = mass / volume = 250 g / 125 cm^3 = 2 g/cm^3. The density of the cube is 2 g/cm^3.
What is the density of a rectangular object with the height of 5 cm the length of 10 cm, the width of 2 cm and the mass of 50 g
Density is defined as mass divided by volume. The volume of a rectangular solid is given by length × width × height, which in this case is 3 cm × 2 cm × 1 cm = 6 cm³. Therefore, the density of the solid is 12 g / 6 cm³ = 2 g/cm³.
The density of the object can be calculated by dividing the mass (40g) by the volume (20 cm³). Therefore, the density of the object is 2 grams per cubic centimeter (g/cm³).
Oh, dude, you're hitting me with some math here! So, the density of the cube is the mass divided by the volume. Since the cube has equal sides, the volume is just side cubed, which is 2 cm x 2 cm x 2 cm. That gives you a volume of 8 cubic cm. Divide the mass (16 grams) by the volume (8 cubic cm), and you get a density of 2 grams per cubic cm. Like, easy peasy, right?