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If you have a rectangular gold brick that is 2 cm by 3 cm by 4 cm and has a mass of 48 g what is the density?
Well, honey, density is mass divided by volume, so in this case, the volume of your gold brick is 2 cm x 3 cm x 4 cm, which equals 24 cm³. So, density = 48 g / 24 cm³, which gives you a density of 2 g/cm³. Voilà!
What is the density of a block of lead that had dimensions of 4.50 cm 5.20 cm 6.00 cm?
To find the density of the block of lead, first calculate its volume using the formula ( \text{Volume} = \text{length} \times \text{width} \times \text{height} ). For the given dimensions, the volume is ( 4.50 , \text{cm} \times 5.20 , \text{cm} \times 6.00 , \text{cm} = 140.4 , \text{cm}^3 ). The density of lead is approximately ( 11.34 , \text{g/cm}^3 ), so the mass of the block can be found by multiplying the volume by the density, resulting in a mass of about ( 1583.9 , \text{g} ). Thus, the density remains ( 11.34 , \text{g/cm}^3 ).
If a cube has a side of 5cm and has a mass of 250 grams what is the density of the cube?
To find the density of the cube, you can use the formula: density = mass/volume. The volume of a cube is calculated as side³, so for a side of 5 cm, the volume is 5 cm × 5 cm × 5 cm = 125 cm³. Given the mass is 250 grams, the density is 250 g / 125 cm³ = 2 g/cm³. Thus, the density of the cube is 2 g/cm³.
A piece of wood that measures 3.0 cm by 6.0 cm by 4.0 cm has a masd of 80.0 grams What is the density of the wood Would thr piece of wood float in water no?
To find the density of the wood, we first calculate its volume using the formula for the volume of a rectangular prism: ( V = length \times width \times height = 3.0 , \text{cm} \times 6.0 , \text{cm} \times 4.0 , \text{cm} = 72.0 , \text{cm}^3 ). Then, we calculate the density using the formula ( \text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{80.0 , \text{g}}{72.0 , \text{cm}^3} \approx 1.11 , \text{g/cm}^3 ). Since the density of water is 1.0 g/cm³, the wood, having a density greater than that, would not float in water.
If an irregular shaped object has a volume of 22cm3 and a mass of 44 g what is the objects density?
Density is calculated using the formula: density = mass/volume. For the irregular object with a mass of 44 g and a volume of 22 cm³, the density would be 44 g / 22 cm³ = 2 g/cm³. Therefore, the object's density is 2 g/cm³.
Find the mass of a piece of ice that is in the shape of a rectangula prism that is 2 cm by 4 cm by 6 cm having a density of 0.92 g cm3?
44.16g density times volume
What is the density of an object that is 10 cm by 2 cm and has a mass 400g?
the density of an object that is 10 cm by 2 cm and has a mass 400g will be 10000 Kg m-3. This can be calculated by the formula, density = mass/volume
If you have a rectangular gold brick that is 2 cm by 3 cm by 4 cm and has a mass of 48 g what is the density?
Well, honey, density is mass divided by volume, so in this case, the volume of your gold brick is 2 cm x 3 cm x 4 cm, which equals 24 cm³. So, density = 48 g / 24 cm³, which gives you a density of 2 g/cm³. Voilà!
What is the density of a cubical block of side 2 cm with a mass 6.4 g?
Density is the mass divided by the volume. The mass is given as 6.4 grm so we have to calculate the volume. A cube of 2 cm per side has a volume of 2 x 2 x 2 equals 8 cm3. Thus the density of the substance is 6.4 divided by 8 equals 0.8 grm per cm3 (in c.g.s units) or 800 Kg per m3 (in SI units) This is less dense than water.
What is the density length10 cm width 5 cm height 2 cm mass 300 g?
The density of the object is 6 g/cm³. Density = mass/volume, mass is 300 g, volume is length x width x height = 10 cm x 5 cm x 2 cm = 100 cm³. Density = 300 g / 100 cm³ = 3 g/cm³.
What is the density of a piece of metal that has a mass of 6.29 times 10 to the power of 5 grams and is 96.4 cm times 49.1 cm times 81.7cm?
The density of this hypothetical metal will be 155,8 g/cm3.
What is the density of a block of lead that had dimensions of 4.50 cm 5.20 cm 6.00 cm?
To find the density of the block of lead, first calculate its volume using the formula ( \text{Volume} = \text{length} \times \text{width} \times \text{height} ). For the given dimensions, the volume is ( 4.50 , \text{cm} \times 5.20 , \text{cm} \times 6.00 , \text{cm} = 140.4 , \text{cm}^3 ). The density of lead is approximately ( 11.34 , \text{g/cm}^3 ), so the mass of the block can be found by multiplying the volume by the density, resulting in a mass of about ( 1583.9 , \text{g} ). Thus, the density remains ( 11.34 , \text{g/cm}^3 ).
A cube has a side 5.0 cm long It has a mass of 250 grams The density of the cube you?
The volume of the cube is (5.0 cm)^3 = 125 cm^3. To find the density, divide the mass by the volume: density = mass / volume = 250 g / 125 cm^3 = 2 g/cm^3. The density of the cube is 2 g/cm^3.
Which will float on a fluid that has a density of 2 grams cm and Acirc and sup3?
Any object which, if submerged, would displace 2 times its own volume. The density of the object could be well above 2 gms/cm^3. If that were not the case, then ships made of metal would never float in water. which has a much lower density.
If a cube has a side of 5cm and has a mass of 250 grams what is the density of the cube?
To find the density of the cube, you can use the formula: density = mass/volume. The volume of a cube is calculated as side³, so for a side of 5 cm, the volume is 5 cm × 5 cm × 5 cm = 125 cm³. Given the mass is 250 grams, the density is 250 g / 125 cm³ = 2 g/cm³. Thus, the density of the cube is 2 g/cm³.
A rectangular solid is 3 cm long 2 cm wide and 1 cm high it has a mass of 12 g what is its density?
The density of a material is defined as its mass per unit volume, density = m/v (mass/volume) One unit for this is grams/cm3. The weight is 12 g, and the volume is: v = 3 cm x 2 cm x 1 cm = 6 cm3 plugging in: density = m/v = 12 g/6cm3 = 2 g/cm3
A piece of wood that measures 3.0 cm by 6.0 cm by 4.0 cm has a masd of 80.0 grams What is the density of the wood Would thr piece of wood float in water no?
To find the density of the wood, we first calculate its volume using the formula for the volume of a rectangular prism: ( V = length \times width \times height = 3.0 , \text{cm} \times 6.0 , \text{cm} \times 4.0 , \text{cm} = 72.0 , \text{cm}^3 ). Then, we calculate the density using the formula ( \text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{80.0 , \text{g}}{72.0 , \text{cm}^3} \approx 1.11 , \text{g/cm}^3 ). Since the density of water is 1.0 g/cm³, the wood, having a density greater than that, would not float in water.
