The idea is to use the addition/subtraction property. In other words, take the derivative of 5x, take the derivative of 1, and subtract the results.
The "double prime", or second derivative of y = 5x, equals zero. The first derivative is 5, a constant. Since the derivative of any constant is zero, the derivative of 5 is zero.
15
(3x2)2 (5x)4 = 9x4625x4 = 5625x8
125x squared
f(x) = 3x2 + 5x + 2fprime(x) = 6x + 5
The derivative of 5x is 5.
I understand this expression to be 10x3 + 5x. Derivative: 30x2 + 5.
x = 10x, so derivative = 10
Derivative with respect to 'x' of (5x)1/2 = (1/2) (5x)-1/2 (5) = 2.5/sqrt(5x)
The idea is to use the addition/subtraction property. In other words, take the derivative of 5x, take the derivative of 1, and subtract the results.
When you subtract 7x^2 from 5x^2, you get -2x^2.
(5x - 2y)(5x + 2y)
The "double prime", or second derivative of y = 5x, equals zero. The first derivative is 5, a constant. Since the derivative of any constant is zero, the derivative of 5 is zero.
The idea is to use the chain rule. Look up the derivative of sec x, and just replace "x" with "5x". Then multiply that with the derivative of 5x.
5x cubed
(5x)2 = 25x2.