The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
This is a difference of two squares, which factorises to: (3x - 4y)(3x + 4y)
All you can do to factor that expression is to divide both terms by y: y2 + 4y = y(y + 4)
7(3y-2)-(-4y+9)
25x+20y=5x(5+4y)
4(y - 3)(y + 3)
The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
This is a difference of two squares, which factorises to: (3x - 4y)(3x + 4y)
It is the difference of two squares which is: (x+2y)(x-2y)
it depends,if y = 0 the answer is -12 if y = 5 then the answer is 368
All you can do to factor that expression is to divide both terms by y: y2 + 4y = y(y + 4)
4(x+y)^2
y2-4y-32 = (y+4)(y-8) when factored
y^(3) - 2y^(2) + 4y Factor out 'y' Hence y(y^2 - 2y + 4) This will not factor any further.
(13x^2 - 4y)(2x^2 - 5y)
7(3y-2)-(-4y+9)
(3x^2 - 4y^2)(3x^2 + 4y^2)