Generally, the derivative to a linear equation (in the form "ax + b") is the constant that is being multiplied by x (in "ax + b", this would be "a"). This is because a derivative gives the slope of a function, and the slope of a linear function is the coefficient next to x. So, in this case, (7x)' = 7.
3
14x
21 X squared over 5
y=7x+1 is a linear equation with a slope of 7 and y-intercept at (0,1). It contains two variables, y and x and cannot be solved unless one variable is given. The x-intercept to this equation is (-1/7,0). The first derivative of the equation would be y=7, a horizontal line with y-intercept (0,7). The second derivative and jerk cannot be taken.
-7x + 5 = -9 -7x = -14 7x = 14 x = 2
3
It is -2*(3x2 - 7)*(x3 - 7x)-3
14x
21 X squared over 5
7x^3. That is 7x cubed.... or 7x*7x*7x (where * means multiply). You should get 343x
y=7x+1 is a linear equation with a slope of 7 and y-intercept at (0,1). It contains two variables, y and x and cannot be solved unless one variable is given. The x-intercept to this equation is (-1/7,0). The first derivative of the equation would be y=7, a horizontal line with y-intercept (0,7). The second derivative and jerk cannot be taken.
1
(7x - 4)(7x + 4).
-7x + 6 + 7x - 2 = 4
None. 7x - 1 is not equal to 7x - 7.
-7x + 5 = -9 -7x = -14 7x = 14 x = 2
3/7x + 5 = 87x(3/7x + 5) = 8(7x)3(7x/7x) + (7x)(5) = 8(7x)3 + 35x = 56x3 + 35x - 35x = 56x - 35x3 = 21x3/21 = 21x/211/7 = x