Take the derivative of (3x+1)1/2
First use the power rule on the entire function, then multiply it by the derivative of the inside:
(1/2)(3x-1)-1/2(3) = (3/2)(3x-1)-1/2
which can also be written as
3/(2sqrt(3x-1))
(sqrt stands for square root)
The square root of x = x to the power of a half
48
No, it is not. It is half of it.
The derivative of 2^x is 2^x * ln2 so the derivative of 2^cosx * ln2 multiplied by d/dx of cox, which is -sinx so the derivative of the inside function is -sinx * 2^cosx *ln2. As to the final question, using the chain rule, d/dx (2^cosx)^0.5 will equal half of (2^cosx)^-0.5 * -sinx * 2^cosx * ln2
-(1/2)X^2 [negative half X squared]
The square root of x = x to the power of a half
x
What is 1/2 of four times Y plus the quantity of Y and 3
You use the same power formula which you use for other powers of x, so the derivate is (1/2)x-1/2. This is the same as 1 / (2 times square root of x).
The answer is obvious. If the quantity of a is equal to the quantity of b then the answer is 12 and a half cents.
48
No, it is not. It is half of it.
Divide the quantity of each of the ingredients in half.
yes u can but it is hard i have done it a coupel of times my selve
A factor of 12 a dozen means 12 therefore half dozen means a quantity of 6 (0.5*12=6) and six dozen means a quantity of 6 times 12 which is 72 (6*12=72)
The derivative of 2^x is 2^x * ln2 so the derivative of 2^cosx * ln2 multiplied by d/dx of cox, which is -sinx so the derivative of the inside function is -sinx * 2^cosx *ln2. As to the final question, using the chain rule, d/dx (2^cosx)^0.5 will equal half of (2^cosx)^-0.5 * -sinx * 2^cosx * ln2
No.