square root of 8
Yes and x = 2+square root of 6 or x = 2-square root of 6
X= plus or minus 1
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
If x squared -10 = 0 then x = the square root of 10
The square root of 28 minus the squared root of 7 =±2.64575131
(x squared plus the square root of 2) times (x squared minus the square root of 2).
square root of 8
5 squared is 25 4 squared is 16 25-16= 9 the square root of 9 is 3.
The square root of 25a squared is 5a. The square root of 16 is 4.So the answer is (5a+4)(5a-4)
Yes and x = 2+square root of 6 or x = 2-square root of 6
X= plus or minus 1
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
a2 + 62 = 122 a2 + 62 - 62 = 122 - 62 a2 = 144 - 36 a2 = 108 taking the square root of each side, we get a equal plus or minus the square root of 108, or plus or minus 6 times the square root of 3.
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
the integral of the square-root of (x-1)2 = x2/2 - x + C
If x squared -10 = 0 then x = the square root of 10