If you mean:
f(x) = x4 - 3x3 + 5x2 / x2
then:
f(x) = x4 - 3x3 + 5
∴ f'(x) = 4x3 - 9x2
If you mean:
f(x) = (x4 - 3x3 + 5x2) / x2
then:
f(x) = x2 - 3x + 5
∴ f'(x) = 2x - 3
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
4
2
21 X squared over 5
( 6x2 / y ) × ( y3 / 12x4) = 6x2y3 / 12x4y = y2 / 2x2
5
1
1
-6
6
4x cubed y cubed z divided by x negative squared y negative 1 z sqaured = 4
X2 (X squared)