(x3)'=3x2(x3)''=(3x2)'=6x
It is -2*(3x2 - 7)*(x3 - 7x)-3
x4/12 since derivative of x4/12 is 4x3/12 or x3/3
if: f(x) = x3 - 4xe-2x Then: f'(x) = 3x2 - [ 4e-2x + 2(4x / -2x) ] = 3x2 - 4e-2x + 4
The derivative of y = 1/3 x3 - 3x2 + 8x + 1/3 is x2 - 6x + 8. You can determine this for yourself by the rules. The derivative of a constant (e.g. 1/3) is 0. The derivative of xn for positive n (actually all nonzero n) is nxn-1. And if the derivative of f(x) is f'(x), then the derivative of k f(x) is k f'(x). Put all these together and you get the above result.
-12sin(x3)x2
(x3)'=3x2(x3)''=(3x2)'=6x
Let y = x3 - 8, then y' = 3x2 + 0 = 3x2.
-4 / x3
It is -2*(3x2 - 7)*(x3 - 7x)-3
If it's tan(x3), the the thingy is 3x2/(cos2(x3)) i think Else, if it's tan(3x), then it's 3/(cos2x) If you need more help with this, search "chain rule" and "derivative" on wikipedia.
0.3333
x*x1/2= x3/2 Derivative = 3/2 * x1/2
If it's tan(x3), the the thingy is 3x2/(cos2(x3)) i think Else, if it's tan(3x), then it's 3/(cos2x) If you need more help with this, search "chain rule" and "derivative" on wikipedia.
d/dx(x4/4) = x3
The volume of a cube is V = x3. The derivative of this is (d/dV)x = 3x2.
The volume of a cube is V = x3. The derivative of this is (d/dV)x = 3x2.