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To find the diagonal of a 40'x60' building, you can use the Pythagorean theorem. The diagonal (d) can be calculated using the formula (d = \sqrt{(length^2 + width^2)}). Plugging in the values, we get (d = \sqrt{(40^2 + 60^2)} = \sqrt{1600 + 3600} = \sqrt{5200}). This simplifies to (d \approx 72.11) feet.
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How many square feet in an area 40feet x 60feet?
to find square feet multiply length by width. in this example 40x60 the answer is square feet 40x60=2400sqft
What is 40x60?
The product is 2400
What is the diagonal measurement of a 20ft x 30ft building?
To find the diagonal measurement of a 20ft x 30ft building, you can use the Pythagorean theorem. The formula is (d = \sqrt{(length^2 + width^2)}). Plugging in the values, (d = \sqrt{(20^2 + 30^2)} = \sqrt{(400 + 900)} = \sqrt{1300} \approx 36.06) feet. Thus, the diagonal measurement is approximately 36.06 feet.
How many square feet of land is 40x60?
If that's 40 x 60 feet, it's 2400 square feet.
If a building is 24ft by 24ft what would the diagnal measurement be?
Using Pythagoras Theorem then the diagonal = √(242 + 242) = √1152 = 33.94 ft (2dp)
