134.6 feet
53.85164807' by means of Pythagoras.
To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem, which states that the square of the length of the diagonal is equal to the sum of the squares of the lengths of the two sides. In this case, the diagonal length (d) can be calculated as follows: d^2 = 30^2 + 50^2. Therefore, d^2 = 900 + 2500 = 3400. Taking the square root of 3400 gives us the diagonal length, which is approximately 58.3 feet.
A rectangle doesn't have a hypotenuse.The diagonal of this one is sqrt(6,100) = 78.1025 (rounded)
Width would be 14 cm
134.6 feet
Use Pythagoras' theorem:- 502+302 = 3400 and the square root of this is the length of the diagonal which is about 58.309 feet to 3 dp
Ah, let's paint a happy little picture here! To find the diagonal of a rectangle, we can use the Pythagorean theorem. So for a 30x40 building, we can calculate the diagonal using the formula: √(30^2 + 40^2) = √(900 + 1600) = √2500 = 50 feet. Just like that, we've added a lovely diagonal to our building!
53.85164807' by means of Pythagoras.
To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem, which states that the square of the length of the diagonal is equal to the sum of the squares of the lengths of the two sides. In this case, the diagonal length (d) can be calculated as follows: d^2 = 30^2 + 50^2. Therefore, d^2 = 900 + 2500 = 3400. Taking the square root of 3400 gives us the diagonal length, which is approximately 58.3 feet.
A rectangle doesn't have a hypotenuse.The diagonal of this one is sqrt(6,100) = 78.1025 (rounded)
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
Width would be 14 cm
To answer the question as written: If the length of a rectangle is given as being 50 feet, then the length of the rectangle is 50 feet. To answer the question that is really being asked, if the width of a rectangle is 12.4 feet and the length of 50 feet, the area can be found by multiplying the length by the width. Therefore, the are of the rectangle would be 620 square feet. If however, the question was to determine the perimeter, you would use the formula 2l+2w=p so you would add 12.4 +12.4+50+50, for a perimeter of 124.8 feet.
15 feet
IF the area is a rectangle, then150 x 50 = 7,500 square feet
If that's a rectangle or a kite, then the perimeter is 50 feet.