The Median and Mean are both measures of the central tendency or average of a group of numbers.
The Median is the middle number of set of numbers arranged in ascending order. If there are an even amount of numbers, find the mean of the middle 2 values. For example the median of 6, 3, 9, 2, 12, 3, 54 is 6, determined by arranging the numbers in the following sequence: 2, 3, 3, 6, 9, 12, 54.
The mean is determined by adding up all the numbers and dividing by the number of numbers. So for the example above, the sum of 2+3+3+6+9+12+54 = 89 Divide 89 by 7 = 12.7 So the mean - often called simple average is 12.7
The mean is most often used to find an average.
the mean is the average of all the salaries an the the median is the number that falls in the middle
The mean, median, and mode are all measures of central tendency. For symmetrical distributions they all have the same value. For assymetrical distributions they have different values. The mean is the average and the mode is the most likely value.
The median is the value which seperates the upper and lower half of a set of numbers. The mean is the average value between two or more numbers. In calculating a set of numbers, specifically a set of averages, the median may indeed be effected by the mean.
The median
First, I will give an example, similar to your question: -11000 -9000 +44000 mean = 8,000 and median = -9000. Symmetrical distributions after infinite sampling will show no difference in mean and median. Large differences are possible with small sample sizes even with symmetrical distributions. If the sample is large and the difference is large, this infers that the distribution is asymmetrical. The skewness of the distribution can be calculated.
the mean is the average of all the salaries an the the median is the number that falls in the middle
There would be a difference to the median. The old number wouldn't be the median but the mode wouldn't change. If the outlier is a high value, it will cause the mean value to shift to the higher side, while a low valued outlier will drop the mean value to a lower number.
The mean, median, and mode are all measures of central tendency. For symmetrical distributions they all have the same value. For assymetrical distributions they have different values. The mean is the average and the mode is the most likely value.
The median is the value which seperates the upper and lower half of a set of numbers. The mean is the average value between two or more numbers. In calculating a set of numbers, specifically a set of averages, the median may indeed be effected by the mean.
The mean is the average, the median is the middle, and the range is the difference between largest and smallest number. These terms are generally used in math.
The median is the middle value of a list of numbers. In [1,6,34] the median value is 6.
Mean = (27+27+29+32+35)/5 = 150/5 = 30 Median = 29 Difference = 1
The median is the middle value of a list of numbers. In [1,6,34] the median value is 6.
The median
As 23 is a single number, its median is itself. If you meant 2 and 3, then the median is 2.5, the value halfway between them, which in this case is also the mean of the two numbers.
First, I will give an example, similar to your question: -11000 -9000 +44000 mean = 8,000 and median = -9000. Symmetrical distributions after infinite sampling will show no difference in mean and median. Large differences are possible with small sample sizes even with symmetrical distributions. If the sample is large and the difference is large, this infers that the distribution is asymmetrical. The skewness of the distribution can be calculated.
You would use median instead of mean because the median doesn't find the average, it finds the middle value. Even if its not the middle of the range (the exact middle value between the lowest number and the highest number) it still is near to the middle value. The mean finds the average of all the numbers, like when a teacher average's her students' grades. Median is better to use when finding the middle value, not the average.