-32 = -(32) = -9
(-3)2 = 9
The difference is 9 - (-9) = 18.
The difference depends on the integers. If the first integer is greater than the second then difference is positive. If the first integer is less than the second then difference is negative. For example 6-4 = +2; 4-6 = -2
No, the difference of two positive integers cannot always be negative. In fact, the difference will be negative only when the first integer is smaller than the second. If the first integer is greater than or equal to the second, the difference will be zero or positive.
The first point has a positive ordinate, the second point has a negative ordinate.
(4x ^2 + 3) + (3x ^2 + 8) = ( 4x^2 + 3x^2 ) + (3+8) = 7x^2 + 11
Difference between first shifting and second shifting theorem
-700
(-5)-2 = 1/(-5)2 = 1/25 = 0.04
(-3)^2 =9 but -3^2 = -9
-3^2 = 9 -(3^2) = -9
You require a pair of negative numbers in which the second has a larger magnitude.For example,8 > 5Then the difference between the negative of the second number and the negative of the first is-5 - (-8) = -5 + 8 = +3
The difference depends on the integers. If the first integer is greater than the second then difference is positive. If the first integer is less than the second then difference is negative. For example 6-4 = +2; 4-6 = -2
If difference is taken to mean the first number minus the second then the answer can be positive or negative (or zero if the two numbers are the same). For example: the difference between -5 and -3 is -2 while the difference between -3 and -5 is +2.
The difference between two negative numbers is negative if the second number ( the number you are subtracting from the first) is less in value than the first. For example (-3) - ( -2) = -3 + 2 = -1 (-3) - (-4) = -3 + 4 = + 1
No, the difference of two positive integers cannot always be negative. In fact, the difference will be negative only when the first integer is smaller than the second. If the first integer is greater than or equal to the second, the difference will be zero or positive.
The first point has a positive ordinate, the second point has a negative ordinate.
You can do this by inspection. If the second number is smaller than the first, their difference is positive. If the second number is greater than the first, then their difference is negative. If the second number is the same as the first number, then their difference is zero.
(4x ^2 + 3) + (3x ^2 + 8) = ( 4x^2 + 3x^2 ) + (3+8) = 7x^2 + 11