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The first 3 digit number divisible by 19 is 114 (= 19 x 6) The last 3 digit number divisible by 19 is 988 (= 19 x 52) That means that there are 52 - 6 + 1 = 47 three digit numbers that are divisible by 19.
19?
It depends which one digit numbers are used. The ten can be any digits from -9 to 9, covering 19 different numbers. If you pick one of those 19 numbers ten times that would be 6131066257801 different possibilities of the number of one digit sets you could make.19*19*19*19*19*19*19*19*19*19=6131066257801
it is 3
100-199 has 19 numbers200-299 has 100 numbers300-399 has 19 numbers400-499 has 19 numbers500-599 has 19 numbers600-699 has 19 numbers700-799 has 19 numbers800-899 has 19 numbers900-999 has 19 numbers(8x19)+100 = 152 + 100 = 252252 three digit numbers contain the digit 2