Let W be any number between 0 and 32.5 (both end points excluded.)
Let L = 65 - W
Then the garden with length L and width W will have a perimeter of 2*(L+W) = 2*(65 - W + W) = 2*65 = 130
Since W can take an infinite number of values, there are an infinite number of possible solutions.
To find the perimeter of a rectangular football pitch, you can use the formula: Perimeter = 2(length + width). For a pitch measuring 90 meters by 40 meters, the calculation is: Perimeter = 2(90 + 40) = 2(130) = 260 meters. Therefore, the perimeter of the football pitch is 260 meters.
40
130 What! How about one tenth of its perimeter?
Assuming you're talking about a rectangle, 452.
Perimeter of a rectanle is the sum of twice the length and twice thewidth. 140 + 140 + 2 x W = 410 2W = 410-280 = 130 W = width = 65 meters
To find the perimeter of a rectangular football pitch, you can use the formula: Perimeter = 2(length + width). For a pitch measuring 90 meters by 40 meters, the calculation is: Perimeter = 2(90 + 40) = 2(130) = 260 meters. Therefore, the perimeter of the football pitch is 260 meters.
40
130 What! How about one tenth of its perimeter?
Assuming you're talking about a rectangle, 452.
Perimeter of a rectanle is the sum of twice the length and twice thewidth. 140 + 140 + 2 x W = 410 2W = 410-280 = 130 W = width = 65 meters
If the width is 65 yards, then the two short ends are 65 yards. 2 x 65 = 130. Take that 130 from 316 to get the total length of the two long sides. That gives you 186. Divide that by 2 to get the length of one side, giving you 93 yards.
You'd need to know one of the sides.
The perimeter of a rectangle measuring 20x45 centimeters is (2*20) + (2*45) = 40 + 90 = 130 cm
A regular pentagon with side length 26 cm has a perimeter of 26*5 = 130 cm. The three sides of the quadrilateral sum to 98.6 cm so the fourth side must be 130-98.6 = 31.4 cm.
Do-it-in-your-head method: Half of 318 is 159, 159 minus 65 is 94 which is your answer, and not an equation in sight!Using the formulaThe formula for Perimeter is: P = 2L + 2W Knowing this, we can substitute and solve:318 = 2L + 2(65) (next simplify)318 = 2L + 130 (next subtract 130 form both sides of the equation)188 =2W (next divide both sides of the equation by 2)94 = WThe width of the rectangle is 94 yards.
Perimeter = 5*26 = 130cm Missing length = 130-23.3-30.4-44.9 = 31.4cm
Let the length be x: 2(x+44) = 218 yards 2x+88 =218 2x = 218-88 2x = 130 x = 65 yards Check: 65+65+44+44 = 218 yards