Let W be any number between 0 and 32.5 (both end points excluded.)
Let L = 65 - W
Then the garden with length L and width W will have a perimeter of 2*(L+W) = 2*(65 - W + W) = 2*65 = 130
Since W can take an infinite number of values, there are an infinite number of possible solutions.
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130 What! How about one tenth of its perimeter?
Assuming you're talking about a rectangle, 452.
Perimeter of a rectanle is the sum of twice the length and twice thewidth. 140 + 140 + 2 x W = 410 2W = 410-280 = 130 W = width = 65 meters
You'd need to know one of the sides.