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Let W be any number between 0 and 32.5 (both end points excluded.)
Let L = 65 - W
Then the garden with length L and width W will have a perimeter of 2*(L+W) = 2*(65 - W + W) = 2*65 = 130
Since W can take an infinite number of values, there are an infinite number of possible solutions.
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Earn +20 ptsQ: What is the dimension of a rectangular garden with a perimeter of 130?
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Continue Learning about Math & Arithmetic
He perimeter 130 if the width is 25 m what is the length?
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If the length is 130 and the width is 96 what is the perimeter?
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What is the width of a rectangular lot that has perimter of 410 meters and a length of 140 meters?
Perimeter of a rectanle is the sum of twice the length and twice thewidth. 140 + 140 + 2 x W = 410 2W = 410-280 = 130 W = width = 65 meters
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