The length of the length will be 5 and the width will be 25.
If "50 inches" is the perimeter all you can say is that length plus width = 25 inches.
To find the perimeter of a rectangle simply add the length and width then double your answer.
Its perimeter is: 2*(10+2.5) = 25 m because its length is 25/2.5 = 10 m
If that's its length and width then its perimeter is: 2*(10+2.5) = 25 m
x=width x+25=length 4x+50=130 4x=80 x=20 width is 20 length is 45
The length of the length will be 5 and the width will be 25.
If "50 inches" is the perimeter all you can say is that length plus width = 25 inches.
For a start at this question, find out how wide this rectangle must be. area (250) = length (25) x width (???) The area of a rectangle is its length times its width. We should divide the area by the length (25) to get the width. The answer is 10. Then we know that each long side is 25 and each short side is 10. We know that in a rectangle, the long sides are the same length and the short sides are the same width. In order to get the perimeter, we add 25 and 25 and 10 and 10. We get 70. So the perimeter is 70.
To find the perimeter of a rectangle simply add the length and width then double your answer.
perimeter = 2 x (width + length) area = width x length If area = perimeter then: width x length = 2 x width + 2 x length width x length - 2 x length = 2 x width length x (width - 2) = 2 x width length = 2 x width / (width - 2) So any rectangle with length and width that satifies the above will work, for example: width = 2.5, length = 10, area: 2.5 x 10 = 25; perimeter: 2x(2.5+10) = 2x12.5 = 25 width = 3, length = 6, area: 3x6 = 18; perimeter: 2x(3+6) = 2x9 = 18 width = 4, length = 4, area: 4x4 = 16; perimeter: 2x(4+4) = 2x8 = 16 By making the length dependent on the width, the width must be at least 2. Once the 4x4 square has been reached, the width becomes larger than the length, but the pair will also be given if the width is the smaller dimension, for example, a width of 6 gives a length of 2 x 6 / (6 - 2) = 12 / 4 = 3, which matches the length of 6 being given by a width of 3.
Assuming that the length is at least as great as the width, the length can have any value, L, between 25 and 50 feet. The width, W, then would be 50 - L feet.
Its perimeter is: 2*(10+2.5) = 25 m because its length is 25/2.5 = 10 m
If that's its length and width then its perimeter is: 2*(10+2.5) = 25 m
37
Let the length be x:- 2(x+4.2) = 25 2x+8.4 = 25 2x = 25-8.4 2x = 16.6 x = 8.3 units of length Check:- Perimeter = 8.3+8.3+4.2+4.2 = 25
To find the width of the rectangle, we need to subtract twice the length from the perimeter. Given that the length is 25 centimeters and the perimeter is 84 centimeters, twice the length would be 50 centimeters. Subtracting 50 from 84 gives us a width of 34 centimeters for the rectangle.