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Using the number line ;-
...-5,-4,-3,-2,-1,0,1,2,3,4,5 ....
Starting at '-3' and moving to the right to '1'. we make '4' steps/
So the distance is '4'. !!!!
What else can I help you with?
What is the distance between the points -4 3 and 3 -1?
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
What is the distance between the points -3 3 and 1 -3?
7.2111 (rounded)
What is the distance between the plotted points 1 3 -1 and .5?
Distance between (1, 3) and (-1, 0.5) = sqrt[(1 - -1)2 + (3 - 0.5)2] = sqrt(22 + 2.52) = sqrt(10.25) = 3.20 approx.
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
What is the distance between these 2 points -3 -1 and 5 -1?
(-3-5)2+(-1--1)2 = 64 and the square root of this is the distance which is 8
What is the distance between 1 and -3 on a number line?
4
What is the distance between (3-4) and (-21)?
3-4 = -1 -21 the distance between -1 and -21 is -20 -20 -1 = -21
What is the distance between (1 3) and (-6 -3)?
3 and 1/2 miles
What is the distance between (1 -3) and (-6 -3)?
3 and 1/2 miles
What is the distance between the points -4 3 and 3 -1?
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
What is the distance between the points -3 3 and 1 -3?
7.2111 (rounded)
What is the distance between the points 3 5 and 1 8?
(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points
What is the distance between the plotted points 1 3 -1 and .5?
Distance between (1, 3) and (-1, 0.5) = sqrt[(1 - -1)2 + (3 - 0.5)2] = sqrt(22 + 2.52) = sqrt(10.25) = 3.20 approx.
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
What is the distance between the points named by (3 1) and (7 1) on the coordinate plane?
Using the distance formula from (3, 1) to (7, 1) is 4 units
What is the distance between the two points -1 5 and 3 7?
The distance between the points is two times the square root of 3.
What is the distance between these 2 points -3 -1 and 5 -1?
(-3-5)2+(-1--1)2 = 64 and the square root of this is the distance which is 8
