The distance is 4
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Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
7.2111 (rounded)
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
Distance between (1, 3) and (-1, 0.5) = sqrt[(1 - -1)2 + (3 - 0.5)2] = sqrt(22 + 2.52) = sqrt(10.25) = 3.20 approx.
(-3-5)2+(-1--1)2 = 64 and the square root of this is the distance which is 8
4
3-4 = -1 -21 the distance between -1 and -21 is -20 -20 -1 = -21
3 and 1/2 miles
3 and 1/2 miles
(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points
The distance between the points is two times the square root of 3.
Using the distance formula from (3, 1) to (7, 1) is 4 units
1
You can get distance and hours and directions from Mapquest.com
There is a distance of 3 between -3 and 0.
The electric force between two charged particles is inversely proportional to the square of the distance between them. If the distance is decreased by a factor of 3, the electric force will increase by a factor of (1/3)^2 = 1/9. This means the force will increase by a factor of 9 when the distance decreases by a factor of 3.
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