The distance is 4
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
7.2111 (rounded)
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
Distance between (1, 3) and (-1, 0.5) = sqrt[(1 - -1)2 + (3 - 0.5)2] = sqrt(22 + 2.52) = sqrt(10.25) = 3.20 approx.
(-3-5)2+(-1--1)2 = 64 and the square root of this is the distance which is 8
4
3-4 = -1 -21 the distance between -1 and -21 is -20 -20 -1 = -21
3 and 1/2 miles
3 and 1/2 miles
(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points
The distance between the points is two times the square root of 3.
Using the distance formula from (3, 1) to (7, 1) is 4 units
1
You can get distance and hours and directions from Mapquest.com
Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
1 over 12