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What is the square root of the distance between points (12) and (x1y1)?
It is [(1 - x1)^2 + (2 - y1)^2]^0.25
What facts are needed to indicate the average slope between two points on a topographic map?
Slope is determined by rise and run. Or the distance between two points, the distance in height (vertical distance) and the lateral distance apart (level distance). If a step has a riser of 6" and a tread of 12", the rise (6") over the run (12") would then become 6/12 or a slope of 45 degrees. 12/12 would be vertical and 0/12 would be horizontal. From horizontal to vertical is 90 degrees. So 6/12 is one half, of 90degrees which is 45 degrees.
What is the distance between points 12 4 and 12 negative 10 on the coordinate plane?
(12, 4) and (12, - 10)Distance = sqrt[(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt[(- 10 - 12)2 + (12 - 12)2]Distance = sqrt(- 22)2Distance = 22==============Could be...(0, 22) as I am not sure here.
What is the distance between the points (10 12) and (minus 4 minus 36)?
Use Pythagoras: distance = √(change_in_x² + change_in_y²) = √((10 - -4)² + (12 - -36)²) = √((10 + 4)² + (12 + 36)²) = √(14² + 48²) = √2500 = 50 units.
What is the distance between two points -8 4 and 4 4?
(-8-4)2 + (4-4)2 = 144 and the square root of this is 12 Answer: 12 units
