If you mean points of (4, 5) and (10, 13) then the distance works out as 10
Points: (2, 2) and (8, -6) Distance: 10
10 units
18 - (-10) = 18 + 10 = 28 units.
10 units.
If the points are (3, 2) and (9, 10) then the distance works out as 10
If you mean points of (4, 5) and (10, 13) then the distance works out as 10
Points: (2, 2) and (8, -6) Distance: 10
10
The distance between points can be calculated using Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((4 - 10)² + (36 - 12)²) → distance = √((-6)² + (24)²) → distance = √(36 + 576) → distance = √612 → distance = 6 √17 ≈ 24.74 units.
If you mean points of: (-6, -10) and (2, 5) then it works out as 17
10 units
The sq.root of 122+162=20
The distance between (4, 5) and (10, 3) = sqrt(40) = 2*sqrt(10) = 6.3246 approx.
10
Points: (22, 27) and (2, -10) Distance using the distance formula: 42.06 rounded to two decimal places
The distance along a straight line is 10. Using the Pythagorean equation, c2 = a2 + b2 where the x change is 6 and the y change is 8, c2 = 62 + 82 = 36 + 64 = 100 c = [sqrt 100] = 10