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Use Pythagoras:

distance = √(change_in_x² + change_in_y²)

= √((10 - -4)² + (12 - -36)²)

= √((10 + 4)² + (12 + 36)²)

= √(14² + 48²)

= √2500

= 50 units.

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Q: What is the distance between the points (10 12) and (minus 4 minus 36)?
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