18 - (-10) = 18 + 10 = 28 units.
If you mean points of (4, 5) and (10, 13) then the distance works out as 10
10 units
10 units.
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
To find the distance between the points (5, 35) and (11, 43) in the xy-plane, you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the values, we get ( d = \sqrt{(11 - 5)^2 + (43 - 35)^2} = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 ). Therefore, the distance between the two points is 10 units.
If you mean points of (4, 5) and (10, 13) then the distance works out as 10
10 units
10 units.
The distance between (4, 5) and (10, 3) = sqrt(40) = 2*sqrt(10) = 6.3246 approx.
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
If you mean points of (5, 5) and (1, 5) then the distance is 4
The distance along a straight line is 10. Using the Pythagorean equation, c2 = a2 + b2 where the x change is 6 and the y change is 8, c2 = 62 + 82 = 36 + 64 = 100 c = [sqrt 100] = 10
If the points are (3, 2) and (9, 10) then the distance works out as 10
Points: (2, 2) and (8, -6) Distance: 10
10
If you mean (4, 5) and (10, 13) then the distance is 10
The distance between points can be calculated using Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((4 - 10)² + (36 - 12)²) → distance = √((-6)² + (24)²) → distance = √(36 + 576) → distance = √612 → distance = 6 √17 ≈ 24.74 units.