10 units.
Distance2 = (21-9)2 + (16-11)2 = 169 and the square root of this is the distance which is 13 units
√((7-3)² + (5 - -2)²) = √(4² + 7²) = √(16+49) = √(65) ≈ 8.062 ■
The distance between two points in a plane can be found using the distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2). In this case, the distance between the points (-1, 2) and (2, 6) is sqrt((2 - (-1))^2 + (6 - 2)^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5.
Using Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((6 - 2)^2 + (3 - 4)^2) = √(16 + 1) = √17 ≈ 4.12
31 - 16 = 15
Distance between the points of (3, 7) and (15, 16) is 15 units
Points: (-4, 5) and (3, 16) Distance: square root of 170 which is about 13
If you mean points of (21, 16) and (9, 11) then the distance works out as 13
If you mean points of (21, 16) and (9, 11) then the distance works out as 13
Distance2 = (21-9)2 + (16-11)2 = 169 and the square root of this is the distance which is 13 units
√((7-3)² + (5 - -2)²) = √(4² + 7²) = √(16+49) = √(65) ≈ 8.062 ■
The distance between two points in a plane can be found using the distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2). In this case, the distance between the points (-1, 2) and (2, 6) is sqrt((2 - (-1))^2 + (6 - 2)^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5.
The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (12) and a vertical distance y2-y1 (-16). The square root of the squares is sqrt [122 + (-16)2] = sqrt [144 + 256] = sq rt [400] = 20.
Using Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((6 - 2)^2 + (3 - 4)^2) = √(16 + 1) = √17 ≈ 4.12
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36
(0, 4) and (- 4, 6) ???Distance = sqrt[(Y2 - Y1)2 + (X2 - X1 )2]Distance = sqrt[(6 - 4)2 + (- 4 - 0)2]Distance = sqrt( 4 + 16)Distance = sqrt(20)==============
Distance = sqrt [(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt [(6 - 4)2 + (- 4 - 0)2]Distance = sqrt [(2)2 + (- 4)2]Distance = sqrt(4 + 16)Distance = sqrt(20)==============