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What is 2 km 90 m?
To convert 2 km 90 m to meters, we first convert 2 km to meters by multiplying 2 by 1000 (1 km = 1000 m), which equals 2000 m. Then, we add the 90 m to get a total of 2090 meters. Therefore, 2 km 90 m is equal to 2090 meters.
What is the m distance of the building at W from the firehouse?
3 1/2
What is the unit for acceleration?
distance/time2, or d/t2
What does d equals 2 m mean?
distance equals two meters
What is the unit of E in E equals mc2?
Units Units of 'E' are kg m^2 s^-2 or kg(m/s)^2 or kg m^2 / s^2 or kg m ( m/s^2) In words it is a mass(kg) multiplied to distance (m) multiplied to acceleration (ms^-2). When Basic S.I. units are arranged in this manner they are referred to a Joules.
What is 2 km 90 m?
To convert 2 km 90 m to meters, we first convert 2 km to meters by multiplying 2 by 1000 (1 km = 1000 m), which equals 2000 m. Then, we add the 90 m to get a total of 2090 meters. Therefore, 2 km 90 m is equal to 2090 meters.
What is long distance swimming?
long distance swimming can meAN 2 things 1 you swim for along distance e.e 1500 m (100m=4lengths) 2 you race in a 50 m pool instead of 25mpool
What is the speed of 50 m in 2 seconds?
Just divide the distance by the time. The answer will be in m/sec.
What is the m distance of the building at W from the firehouse?
3 1/2
What is reverses direction and rolls 8 m north The car has traveled a distance of 18 m and has a displacement of m south?
2
The amplitude of a particular wave is 1 m the top to bottom distance of the disturbance is?
The top to bottom distance of the disturbance would be 2 meters since amplitude represents half of this full distance.
What is the unit for acceleration?
distance/time2, or d/t2
What does d equals 2 m mean?
distance equals two meters
What is the distance around M M and M?
None. M, M and M are the same so they are coincident and, consequently, the distance around them is zero.
What two factors does the strength of gravity depends?
The masses, and the distance. The formula for gravitional attraction is: F = G m(1) m(2) / r2, where G is a constant, m(1) and m(2) are the two masses, and r is the distance.
What will the stopping distance for 1000-kg car moving 20 ms when you apply a force of -500 N?
Given a force of -500 N, which implies braking, the stopping distance of the car can be calculated using the equation ( d = v^2 / 2a ), where ( d ) is the stopping distance, ( v ) is the initial velocity (20 m/s), and ( a ) is the acceleration produced by the force. Using Newton's second law, we have ( a = F / m = -500 / 1000 = -0.5 , \text{m/s}^2 ). Substituting ( v = 20 , \text{m/s} ) and ( a = -0.5 , \text{m/s}^2 ) into the stopping distance equation, we get ( d = 20^2 / (2 \times 0.5) = 400 , \text{m} ). Hence, the stopping distance for the car will be 400 meters.
A jogger runs at an average speed of 5 ms for 3 minutes then finishes with an average speed of 4 ms for 2 minutes What is his average speed in ms for the run?
The total distance covered by the jogger is the sum of the distances covered in the first 3 minutes and the last 2 minutes. Using the formula distance = speed × time, the total distance is 5 m/s × 3 min + 4 m/s × 2 min = 15 m + 8 m = 23 m. The total time taken is 3 min + 2 min = 5 min. Therefore, the average speed is total distance / total time = 23 m / 5 min = 4.6 m/s.
