Wiki User
∙ 12y agoAssuming you mean sqrt(x-3) rather than sqrt(x) - 3, the domain can be any subset of of x ≥ 3. The range will depend on the domain but needs to be divided in two so that it contains only one of the two roots.
Wiki User
∙ 12y agoDomain is greater than or equal to zero. same with range
The domain is (-infinity, infinity) The range is (-3, infinity) and the asymptote is y = -3
domain: (-infinity to infinity) range: ( -infinity to infinity)
The domain would be (...-2,-1,0,1,2...); the range: (12)
domain: all real numbers range: {5}
The domain and the range depends on the context. For example, the domain and the range can be the whole of the complex field. Or I could define the domain as {-2, 1, 5} and then the range would be {0, 3, -21}. When either one of the range and domain is defined, the other is implied.
x
The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, ∞).
Domain is greater than or equal to zero. same with range
The domain is (-infinity, infinity) The range is (-3, infinity) and the asymptote is y = -3
In the complex field, the domain and range are both the whole of the complex field.If restricted to real numbers, the domain is x >= 4 and y can be all real numbers >= 0 or all real numbers <= 0 [or some zigzagging pattern of that set].
The domain could be the real numbers, in which case, the range would be the non-negative real numbers.
Domian is x>-6 Range is y> or equal to 0
domain: (-infinity to infinity) range: ( -infinity to infinity)
The domain would be (...-2,-1,0,1,2...); the range: (12)
domain: all real numbers range: {5}
The Domain and Range are both the set of real numbers.