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What is the square root of 24x to the 4th power divided by the square root of 3x?
√(24x)4/√(3x) = [242x2√(3x)]/3x = 8(24)x√(3x) = 192x√(3x)
Square root 24x4 divided by square root 3x?
Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
Square root of 24 times x to the 4th power divided by square root 3x?
The question is ambiguous. Do you mean √(24*x4) or √24*x4? √(3x) or √3*x? The answer to √(24*x4) / √(3x) = (8x3) = 2x*√(2x)
What is the domain of the square root of 3x 3?
Assuming you mean 3x3: If you work with real numbers, anything under the square root sign must be non-negative, so if you solve the inequality: 3x3 >= 0 for x, you get all valid values of x for this function, in other words, the domain.
9 x squared plus 3 x divided by 3 x?
9x2 + 3x / 3x equals (3x + 1).9x2 + 3x divided by x is 9x + 3 , and then divided by 3 yields the 3x +1.
What is the square root of 24x to the 4th power divided by the square root of 3x?
√(24x)4/√(3x) = [242x2√(3x)]/3x = 8(24)x√(3x) = 192x√(3x)
Square root 24x4 divided by square root 3x?
Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
How do you factor 3x4 minus 12x3 plus 4x minus 16 and find the complex zeros?
(x - 4)(3x^3 + 4) The complex roots are the cube root of negative one third times two to the two thirds power and negative two to the two thirds power divided by the cube root of three
How do you factor 9x squared plus 25?
9x2 + 25 has no rational factors. Its factorisation in the complex domain is:(3x + 5i)*(3x - 5i) where i is the imaginary square root of -1.
Square root of 24 times x to the 4th power divided by square root 3x?
The question is ambiguous. Do you mean √(24*x4) or √24*x4? √(3x) or √3*x? The answer to √(24*x4) / √(3x) = (8x3) = 2x*√(2x)
What is the definition of a cube root?
The cube root for a real number is the value that when multiplied by itself three times produces that number. So that the cube root of B is A where A x A x A = B.Examplesthe cube root of 8 is 2... (2x2x2=8)the cube root of 27 is 3...(3x3x3=27)The special cases are 0 and 1, which are by definition their own roots (square roots, cube roots, etc.) because all powers of 0 and 1 are still the same value, zero or 1.Perfect cubes are numbers that can be cube-rooted into an integer.These include the numbers 0, 1, 8, 27, and so forth.Negative numbers can also be perfect cubes.-1x-1x-1=-1-2x-2x-2=-8-3x-3x-3=-27For non-perfect cubes, the root includes a repeating decimal requiring rounding.
What is 2 divided by 3x?
If 2 divided by 3x it is equal to 2/3x
What is the answer to square root of 75x - square root of 48x?
27
What is the domain of the square root of 3x 3?
Assuming you mean 3x3: If you work with real numbers, anything under the square root sign must be non-negative, so if you solve the inequality: 3x3 >= 0 for x, you get all valid values of x for this function, in other words, the domain.
9 x squared plus 3 x divided by 3 x?
9x2 + 3x / 3x equals (3x + 1).9x2 + 3x divided by x is 9x + 3 , and then divided by 3 yields the 3x +1.
What is the square root of 12x?
2 root 3x
What is the surface area of a cube with an edge of 3x centimeters long?
6*(the area of one side) 6*(3x*3x) 6*(9x2) 54x2
