The domain is all real numbers except 0.
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∙ 15y ago√(24x)4/√(3x) = [242x2√(3x)]/3x = 8(24)x√(3x) = 192x√(3x)
Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
The question is ambiguous. Do you mean √(24*x4) or √24*x4? √(3x) or √3*x? The answer to √(24*x4) / √(3x) = (8x3) = 2x*√(2x)
9x2 + 3x / 3x equals (3x + 1).9x2 + 3x divided by x is 9x + 3 , and then divided by 3 yields the 3x +1.
Assuming you mean 3x3: If you work with real numbers, anything under the square root sign must be non-negative, so if you solve the inequality: 3x3 >= 0 for x, you get all valid values of x for this function, in other words, the domain.
√(24x)4/√(3x) = [242x2√(3x)]/3x = 8(24)x√(3x) = 192x√(3x)
Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
(x - 4)(3x^3 + 4) The complex roots are the cube root of negative one third times two to the two thirds power and negative two to the two thirds power divided by the cube root of three
9x2 + 25 has no rational factors. Its factorisation in the complex domain is:(3x + 5i)*(3x - 5i) where i is the imaginary square root of -1.
The question is ambiguous. Do you mean √(24*x4) or √24*x4? √(3x) or √3*x? The answer to √(24*x4) / √(3x) = (8x3) = 2x*√(2x)
The cube root for a real number is the value that when multiplied by itself three times produces that number. So that the cube root of B is A where A x A x A = B.Examplesthe cube root of 8 is 2... (2x2x2=8)the cube root of 27 is 3...(3x3x3=27)The special cases are 0 and 1, which are by definition their own roots (square roots, cube roots, etc.) because all powers of 0 and 1 are still the same value, zero or 1.Perfect cubes are numbers that can be cube-rooted into an integer.These include the numbers 0, 1, 8, 27, and so forth.Negative numbers can also be perfect cubes.-1x-1x-1=-1-2x-2x-2=-8-3x-3x-3=-27For non-perfect cubes, the root includes a repeating decimal requiring rounding.
If 2 divided by 3x it is equal to 2/3x
27
9x2 + 3x / 3x equals (3x + 1).9x2 + 3x divided by x is 9x + 3 , and then divided by 3 yields the 3x +1.
Assuming you mean 3x3: If you work with real numbers, anything under the square root sign must be non-negative, so if you solve the inequality: 3x3 >= 0 for x, you get all valid values of x for this function, in other words, the domain.
6*(the area of one side) 6*(3x*3x) 6*(9x2) 54x2
2 root 3x