3x y^3
Square root of 3=1 so 1+4=5
it is greater than and equal to 3
The question is ambiguous. Do you mean √(24*x4) or √24*x4? √(3x) or √3*x? The answer to √(24*x4) / √(3x) = (8x3) = 2x*√(2x)
x2 + 3x + 3 = 0 doesn't factor neatly. Applying the quadratic formula we find two imaginary solutions: (-3 plus or minus the square root of -3) divided by 2x = -1.5 + 0.8660254037844386ix = -1.5 - 0.8660254037844386iwhere i is the square root of negative 1
No. The Square root of x is not the value of x. So it can not be simplified beyond: Root X + root 3x Yes. The square root of 3x equals the square root of 3 times the square root of x, so when you add another square root of x, you can factor out the square root of x, thereby simplifying the expression to the square root of x times the sum of one plus the square root of three.
3x y^3
3x^2 = 44 divide both sides by 3; x^2 == 44/3 x = +,- square root of 44/3 write 44 = 4 x 11; x = +,- 2(square root of 11/3) multiply the square root of 11/3 by square root of 3/3; x = +,- (2/3)(square root of 33)
√(3x - 5) = 3 ∴3x - 5 = 9 ∴3x = 14 ∴x = 14/3
Square root of 3=1 so 1+4=5
it is greater than and equal to 3
The question is ambiguous. Do you mean √(24*x4) or √24*x4? √(3x) or √3*x? The answer to √(24*x4) / √(3x) = (8x3) = 2x*√(2x)
x2 + 3x + 3 = 0 doesn't factor neatly. Applying the quadratic formula we find two imaginary solutions: (-3 plus or minus the square root of -3) divided by 2x = -1.5 + 0.8660254037844386ix = -1.5 - 0.8660254037844386iwhere i is the square root of negative 1
3x2 = 27Divide each side by 3:x2 = 9Take the square root of each side:x = + 9x = - 9
square root 2 times square root 3 times square root 8
Square root (75) / square root (3) = 5
In real numbers, the two answers are, approximately, - 1.73205 and + 1.73205 (the two square roots of +3) But in the complex domain you also have - 1.73205*i and + 1.73205*i where i is the imaginary square root of -1.