There is no easy way or really, any way at all to memorize an infinite list.
Becasue the given number is a compound number because it can be divivded by '2' Remember all 'EVEN' numbers are those ending in 0,2,4,6,8 are even and can be divided by '2'. Except for '2' itself, all prime numbers are odd.
6480 is NOT a Prime Number.#Reason it is a multiple of '2'. Remember the only even prime number is '2' All other prime numbers are odd numbers. Even numbers end in 0,2,4,6,8 Odd numbers end in 1,3,5,7,9
The smallest prime number in which all of the digits are also prime is 2.The smallest multi-digit prime number in which all of the digits are also prime is 23.
do the prime factorization of the 3 numbers. list the prime factors of all the 3 numbers. circle the factors that are common to the 3. multiply them. that number is the HCF
It is always 1 and the prime number itself.
A prime number is one that is only divisible by 1 and itself. Just work out if it divides into anything. To do this try dividing the number by all prime numbers under its half way value.
Becasue the given number is a compound number because it can be divivded by '2' Remember all 'EVEN' numbers are those ending in 0,2,4,6,8 are even and can be divided by '2'. Except for '2' itself, all prime numbers are odd.
6480 is NOT a Prime Number.#Reason it is a multiple of '2'. Remember the only even prime number is '2' All other prime numbers are odd numbers. Even numbers end in 0,2,4,6,8 Odd numbers end in 1,3,5,7,9
The easiest, but not the most efficient way, to program this is to take your number "n" and test all the numbers from 2 to n-1 to see if they divide n, if none of them do, then n is prime.
The smallest prime number in which all of the digits are also prime is 2.The smallest multi-digit prime number in which all of the digits are also prime is 23.
All prime numbers are going to be deficient, because remember that a prime number's only factors are one and itself. To find if its deficient or abundant, you'd add up all of its factors, excluding itself. If its only other factor beside itself is one, that's obviously less than the number, and therefore it will be deficient.
do the prime factorization of the 3 numbers. list the prime factors of all the 3 numbers. circle the factors that are common to the 3. multiply them. that number is the HCF
It is always 1 and the prime number itself.
47 is already a prime number.
No, all prime numbers are deficient.
The number 1 and the prime number itself.
No, all prime numbers are deficient.