Suppose one end point is A and the midpoint is M.
Then the distance from the given end to the midpoint is M-A.
So the other end point is M-A further away from M ie it is at M + (M-A) = 2M-A.
The above answer looks like it is for 1 dimensional problems only but for two or more dimensions, either treat A and M as vectors or (if you are not familiar with vectors), apply the same rule to the x-coordinate, then separately, to the y-coordinate, etc.
So, in 2 dimensions,
if A = (ax, ay) and M = (mx, my)
then the other end point is (2mx- ax , 2my- ay)
and similarly for more dimensions.
A line segment has endpoints and a midpoint.
Yes
it gives you the midpoint of the line segment you use the formula for
At the end of the line there needs to be two points. Measure the line and divide by two.
There are only three endpoint given and these are not sufficient to define a segment of a line.
A line segment has endpoints and a midpoint.
If you are only given one endpoint and a midpoint, you know what the middle of the line segment is. Since the midpoint is half of what the line segment's length is, all you have to do is find the distance between the endpoint given and the midpoint, then add that coordinate to your midpoint and get your other endpoint. For example: Endpoint A: (4,5) Midpoint: (6,8) Distance between: (2,3) Add (2,3) to (6,8) and get Endpoint B: (8,11).
If you mean endpoint (6, 9) and midpoint (7, 6) then the other endpoint is (8, 3)
Yes
it gives you the midpoint of the line segment you use the formula for
(9,4)
No. The midpoint of a line segment is the single point exactly halfway between each endpoint.
The formula for finding the midpoint of a line segment using midpoint notation is: M ((x1 x2) / 2, (y1 y2) / 2)
Endpoints: (-2,-2) and (4, 6) Midpoint: (1, 2)
At the end of the line there needs to be two points. Measure the line and divide by two.
If you mean endpoints of (-5.5, -6.1) and (-0.5, 9.1) Then the midpoint is at: (-3, 1.5)
There are only three endpoint given and these are not sufficient to define a segment of a line.