Points: (3, 5) and (7, 11) Midpoint: (5, 8) Slope: 3/2 Perpendicular slope: -2/3 Perpendicular equation: y-8=-2/3(x-5) => 3y-24=-2x+10 => 3y=-2x+34 Therefore the perpendicular bisector equation is: 3y = -2x+34
1+11 2+10 3+9 4+8 5+7 6+6 7+5 8+4 9+3 2+10 11+1 That's all of them, without going into negatives
Where parentheses can be rearranged and do no change the equation. 5*(8*2)=(8*5)*2
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12
8*(5+11)/(2+6)= 8(16)/8= 16
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-1 = -3/4(x--5) => 4y = -3x-11 Perpendicular bisector equation in its general form: 3x+4y+11 = 0
Points: (3, 5) and (7, 11) Midpoint: (5, 8) Slope: 3/2 Perpendicular slope: -2/3 Perpendicular equation: y-8=-2/3(x-5) => 3y-24=-2x+10 => 3y=-2x+34 Therefore the perpendicular bisector equation is: 3y = -2x+34
1+11 2+10 3+9 4+8 5+7 6+6 7+5 8+4 9+3 2+10 11+1 That's all of them, without going into negatives
Where parentheses can be rearranged and do no change the equation. 5*(8*2)=(8*5)*2
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12
find the sum and product of the roots of 8×2+4×+5=0
8*(5+11)/(2+6)= 8(16)/8= 16
27.5
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12
5 5/8 = 5 5/8 , 2 3/4 = 2 6/8 5 5/8 + 2 6/8 = 7 11/8 7 11/8 = 8 3/8
2