SolutionBrine = H2O + NaCl
NH4OH < == > NH3 + H2O, it is a weak base
liho+h2s=
The reactants are the substances that react together; the reactants are on the left side of the equation. The product (or products) are what is produced from the reaction, which is on the right side of the equation. For example: 2H2 + O2 --> 2(H2O) The reactants are H2 & O2 and the product is H2O
8H+ + MnO4- + 5Fe2+--> 5Fe3+ + Mn2+ + 4H20
The chemical equation for potassium bicarbonate (KHCO3) reacting with nitric acid (HNO3) is KHCO3 + HNO3 → KNO3 + H2O + CO2.
The ionic equation for HCl and KHCO3 is H+(aq) + Cl-(aq) + K+(aq) + HCO3-(aq) → KCl(aq) + H2O(l) + CO2(g). The net ionic equation is H+(aq) + HCO3-(aq) → H2O(l) + CO2(g).
The chemical equation for Na2S (sodium sulfide) reacting with H2O (water) is: Na2S + H2O → 2NaOH + H2S
2K + H2O ----> K2O + H2
The balanced symbol equation for copper II oxide reacting with hydrogen is Cu + H2O. This reaction will create copper and water as a result.
The balanced chemical equation for acetic acid (HC2H3O2) in vinegar reacting with potassium hydroxide (KOH) is: HC2H3O2 + KOH -> KC2H3O2 + H2O This balanced equation shows that one molecule of acetic acid reacts with one molecule of potassium hydroxide to form one molecule of potassium acetate and one molecule of water.
The balanced equation is 2KHCO3(s) → K2CO3(s) + H2O(g) + CO2(g). The coefficient of carbon dioxide (CO2) in the balanced equation is 1.
When potassium bicarbonate (KHCO3) reacts with hydrobromic acid (HBr), the products formed are potassium bromide (KBr), water (H2O), and carbon dioxide (CO2).
A possible equation should be:2 Fr + 2 H2O = 2 FrOH + H2
The chemical formula for potassium bicarbonate is KHCO3.
The balanced equation for potassium oxide (K2O) reacting with carbonic acid (H2CO3) is: K2O + H2CO3 -> 2KOH + CO2
Ca(OH)2 + H2SO4 = CaSO4 + 2 H2O