What role of operations that applies when you are solving an equation does not apply when your solving an inequality?"
By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.
Ask someone eles.
An equality and equation are essentially the same thing. The equality between two expressions is represented by an equation (and conversely).
the equation for a triangle is 1/2base*height knowing that it's a simple equation solving for a single unknown.
What role of operations that applies when you are solving an equation does not apply when your solving an inequality?"
No because you always keep an equation in balance when solving it
To tackle this you first need to know the equations for both volume and surface area. The surface area of a cube is 6x2 where x is the side length. The volume of the cube is x3. Thus x is the cube root of the volume. We can substitute this in to the surface area equation and say that the surface area of a cube is 6volume2/3 This can also be rearranged to say that the volume of the cube is (the surface area/6)1.5
By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.
It is the solution of the equation
cube square -8
Ask someone eles.
An equality and equation are essentially the same thing. The equality between two expressions is represented by an equation (and conversely).
the equation for a triangle is 1/2base*height knowing that it's a simple equation solving for a single unknown.
An equation is a mathematical statement that may (or may not) be true, defined for some variables. Solving an equation is finding those values of the variables for which the equation or statement is true.
Your problem is quite easy...Since getting the volume of a cube is s3 we will do the opposite of it will get its cube root* First get the cube root of 25 = 2.9 (I just round it off but the exact measure is 2.924017738) * Then use the formula 6s2 for solving the surface area SA = (6)(2.9)2= (6)(8.41)SA = 50.46
A radical equation is an equation that contains a variable inside a radical, such as a square root or a cube root. Solving radical equations involves isolating the radical term and then squaring both sides of the equation to eliminate the radical. It is important to check for extraneous solutions when solving radical equations.