(number of sides - 2)*180 = total sum of interior angles
No, any polygon.
The sum of the interior angles is (n-2)*180 degrees.
The sum of one angle is simply the measure of that angle.
A quadralateral is a polygon with four angles. I think what you mean is "Do all quadralaterals have an angle sum of 360 degrees?". Yes they do, you can determine the angle sum of a polygon with this formula: s=(n-2)180 s is the angle sum while n is the number of sides, I hope this helps.
formula for exterior angle=no.sides divided by 360. formula for interior angle=180 minus exterior angle.
(n-2)(180) use that formula to find the sum of the interior angles of a polygon in degree
(number of sides - 2)*180 = total sum of interior angles
Using the quadratic equation formula and Pythagoras' theorem it works out as 13.75 cm in length
No, any polygon.
The formula to find the sum of the angles of any shape is: (sideCount-2)*180 If the shape has 11 sides the total interior angle is: 1620.
The sum of the interior angles is (n-2)*180 degrees.
To calculate the sum of the numbers 1 to n, the formula is: sum = n(1 + n) / 2 So, an equation to find the sum of the integers 1 to 2010 is: sum = 2010 x (1 + 2010) / 2
The formula is (n-2)x180 over n =x
Angle and its complement have a sum of 90 degrees: A+C = 90 Angle plus five times its complement is 298 degrees: A+5C = 298 Subtract first equation from the second: 4C = 208 C = 52 So, the complement is 52 degrees and the angle is 38 degrees
A polygon with an angle sum of 5940o would have 1,069,198 sides.The equation to find the angle sum of a polygon is (n - 2) / 180We can substitute the figures we know and solve as for an ordinary linear equation by rearranging to isolate the n as our variable.(n - 2 ) / 180 = 5940(n - 2 ) = 5940 * 180n - 2 = 1,069,200n = 1,069,200 - 2= 1,069,198So a polygon that has an angle sum of 5940o would have 1,069,198 sides.
For any polygon: 180-interior angle = exterior angle and the exterior angles of any polygon add up to 360 degrees