To calculate the sum of the numbers 1 to n, the formula is:
sum = n(1 + n) / 2
So, an equation to find the sum of the integers 1 to 2010 is:
sum = 2010 x (1 + 2010) / 2
Let the first integer be x. Since the integers are consecutive odds we know that the integers are x, x+2, x+4,and x+6. Since the sum of all of these is 200 we can set up the equation:4x+12 = 200. Solving we get x=47. Therefore the integers are 47, 49, 51, and 53.
No. All whole numbers are integers and all integers are whole numbers.
The set of all values of x, for which the equation is true is the domain of the function defined by that equation.
The sum of the integers 1 to 99 is 4950. An easy way to figure this out is using the equation N*(N+1)/2 where N is the largest number in the set.
All natural numbers are integers, not all integers are natural numbers.
There is no such thing as "solving integers". You can solve an equation, which means finding all the unknowns in that equation, but you can't solve an integer.
Yes, it is an integer sequence.
It is a trivial difference. If you multiply every term in the equation with rational numbers by the common multiple of all the rational numbers then you will have an equation with integers.
To find the average of integers, add them all together then divide the total by the number of integers.
Let the first integer be x. Since the integers are consecutive odds we know that the integers are x, x+2, x+4,and x+6. Since the sum of all of these is 200 we can set up the equation:4x+12 = 200. Solving we get x=47. Therefore the integers are 47, 49, 51, and 53.
By adding whatever you mean with "integers of a number".
You solve the equation.
Write a program to find the number and sum of all integers from 100 to 300 that are divisible by 11
16+18+20= 54
Dude, stop trying to cheat on your own maths enrichment task loser.
At least the following families: all integers; all positive integers; all odd integers; and all "square integers", that is, integers that are squares of other integers.
All integers are rational numbers.